\(\frac{6.804^6*1.701^{-13}}{2^{19}*3.402^{-7}}=\frac{(2^2*1.701)^6}{2^{19}*(2*1.701)^{-7}*1.701^{13}}=\frac{2^{12}*1.701^6*(2*1.701)^{7}}{2^{19}*1.701^{13}}=\frac{2^{12}*1.701^6*2^7*1.701^{7}}{2^{19}*1.701^{13}}=\frac{2^{19}*1.701^{13}}{2^{19}*1.701^{13}}=1\).

Answer: B.

Please do check the questions when posting and use formating for such formulas (writing-mathematical-symbols-in-posts-72468.html).
_________________

I'm sure the question must have \((6.804)^6\) in the numerator; otherwise you won't have much simplification. I also suspect that the denominator should have a 2^19 in it, instead of 2^9; otherwise you won't get one of the five answer choices. With those changes, then if you notice that 3.402 = 2(1.701), and that 6.804 = (2^2)(1.701), we can factor out 2's in order to cancel:

\(\frac{(6.804)^6 (1.701)^{-13}}{(2^{19})(3.402)^{-7}} = \frac{(2^2)^6(1.701)^6 (1.701)^{-13}}{(2^{19})(2^{-7})(1.701)^{-7}} = \frac{(2^{12})(1.701)^{-7}}{(2^{12})(1.701)^{-7}} = 1\)
_________________

Edited the original post. Thank you.
_________________

Re-writing the equation in the powers of 1.701 & 2 :

2^12 . 1.701^6 . 1.701^ -13

Divide by

2^19 . 2^ -7 . 1.701^-7

Answer = 1 = B

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________