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# (7.25-1.25)/...

Author Message
Senior Manager
Status: 1,750 Q's attempted and counting
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Joined: 09 Jul 2013
Posts: 493
Location: United States (FL)
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GMAT 1: 600 Q45 V29
GMAT 2: 590 Q35 V35
GMAT 3: 570 Q42 V28
GMAT 4: 610 Q44 V30
GPA: 3.45
WE: Accounting (Accounting)

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Updated on: 14 Feb 2019, 15:55
2
00:00

Difficulty:

5% (low)

Question Stats:

93% (01:15) correct 7% (01:34) wrong based on 56 sessions

### HideShow timer Statistics

[IMAGE with Question is MISSING ]

A. 0.75
B 1.5
C. 2.25
D. 3
E. 3.75

Originally posted by avohden on 02 Oct 2013, 15:23.
Last edited by bb on 14 Feb 2019, 15:55, edited 1 time in total.
Senior Manager
Status: 1,750 Q's attempted and counting
Affiliations: University of Florida
Joined: 09 Jul 2013
Posts: 493
Location: United States (FL)
Schools: UFL (A)
GMAT 1: 600 Q45 V29
GMAT 2: 590 Q35 V35
GMAT 3: 570 Q42 V28
GMAT 4: 610 Q44 V30
GPA: 3.45
WE: Accounting (Accounting)

### Show Tags

02 Oct 2013, 15:32
1
Official Explanation

Let's take this problem one fraction at a time. Looking at the first fraction, you we can easily simplify the numerator: 7.25 – 1.25 = 6. In the denominator,. So , and the first fraction is equal to 0.75 (written as a decimal). Now take the second fraction. In the numerator, .In the denominator, (3)(4) = 12. So , and the second fraction is also equal to 0.75. Looking at the third fraction, remember that . So this fraction also equals , or 0.75. Adding, 0.75 + 0.75 + 0.75 = 2.25, and the correct answer is thus choice (C).
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02 Oct 2013, 19:34
Option C. The provided explanation is correct; Each term simplifies to 3/4 or 0.75 & 3 times 0.75 gives us 2.25 --> Option C
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28 Oct 2014, 00:23
Simplifying:

$$\frac{3}{4} + \frac{3}{4} + \frac{3}{4} = \frac{9}{4} = \frac{225}{100} = 2.25$$

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29 Oct 2014, 13:19
Just wondering how you guys assumed the square root of the numbers are only positive? Isn't it possible to have a combination of negative roots as well? Thanks!
Manager
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29 Oct 2014, 21:06
gmatchess wrote:
Just wondering how you guys assumed the square root of the numbers are only positive? Isn't it possible to have a combination of negative roots as well? Thanks!

As far as GMAT is concerned

Root of a "Number" is always +ve i.e. \sqrt{9} = 3

However, \sqrt{X^2} = Mod X = +/- X
Math Expert
Joined: 02 Sep 2009
Posts: 52910

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30 Oct 2014, 01:57
1
gmatchess wrote:
Just wondering how you guys assumed the square root of the numbers are only positive? Isn't it possible to have a combination of negative roots as well? Thanks!

When the GMAT provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the positive root.

That is:
$$\sqrt{9} = 3$$, NOT +3 or -3;
$$\sqrt[4]{16} = 2$$, NOT +2 or -2;

Notice that in contrast, the equation $$x^2 = 9$$ has TWO solutions, +3 and -3. Because $$x^2 = 9$$ means that $$x =-\sqrt{9}=-3$$ or $$x=\sqrt{9}=3$$.

Hope it's clear.
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08 Feb 2019, 23:12
1
avohden wrote:

A. 0.75
B 1.5
C. 2.25
D. 3
E. 3.75

Dear Moderator,
The image in this question is not visible.Hope you will do the needful.Thank you.
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- Stne

(7.25-1.25)/...   [#permalink] 08 Feb 2019, 23:12
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