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correct 45%
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A 20 kilograms mixture of dry fruits consisting of x percent of almonds is formed by mixing 'a' kilograms of mixture A and 'b' kilograms of mixture B. If mixture A consists of 'y' percent of almonds and mixture B consists of 20% of almonds, what is the weight of almonds in kilograms in mixture A? Assume that each mixture has a uniform composition, that is, samples taken from any part in a mixture will have the same composition as the overall mixture.
(1) The amount of almonds in mixture B is three-fifths of the total weight of mixture A
(2) If the weight of the final mixture is reduced by 25 percent, the almonds in the final mixture would reduce by 1.5 kilograms
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A 20 kilograms mixture of dry fruits consisting of x percent of almonds is formed by mixing 'a' kilograms of mixture A and 'b' kilograms of mixture B. If mixture A consists of 'y' percent of almonds and mixture B consists of 20% of almonds, what is the weight of almonds in kilograms in mixture A? Assume that each mixture has a uniform composition, that is, samples taken from any part in a mixture will have the same composition as the overall mixture.
(1) The amount of almonds in mixture B is three-fifths of the total weight of mixture A
(2) If the weight of the final mixture is reduced by 25 percent, the almonds in the final mixture would reduce by 1.5 kilograms
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so WHAT do we have here..
Final mixture of 20 kgs having x% of almonds 1) a kg of mix A consisting of y% of almonds 2) b kg of B mix containing of 20% of almonds...
weight of almonds in mix A - REQUIRES the value of 'a' and 'y'..
lets see the statements:-
(1) The amount of almonds in mixture B is three-fifths of the total weight of mixture A this gives me the equation \(0.2b=\frac{3}{5}a........b=3a\) so I know now that b is 15 and a is 5.. but I still do not know the value of y as there are two variables in % - x and y insuff
(2) If the weight of the final mixture is reduced by 25 percent, the almonds in the final mixture would reduce by 1.5 kilograms so 25% reduction means reduction of 5 kgs and in 5 kgs I have 1.5 kg almonds, so % of almonds in final mix or \(x = \frac{1.5}{5}*100\) here I have x But y will depend on the ratio of weights of a and b.. insuff
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