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Difficulty:
75%
(hard)
Question Stats:
43%
(02:42)
correct 57%
(02:56)
wrong
based on 21
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A bag contains red balls that weigh 100 grams each and green balls that weigh 50 grams each. If the number of green balls is 9 more than the number of red balls, how many balls are there in the bag?
I. If two red balls are added to the bag, the number of red balls will be half the number of green balls
II. The total weight of the balls in the bag is between 1.05 kilogram and 1.35 kilogram
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Let number of red balls be x Then the number of green balls is (x+9)
Statement 1:
If two red balls are added to the bag, the number of red balls will be half the number of green balls.
The new number of red balls is (x +2) So, (x + 2) = (x + 9)/2 => 2x + 4 = x + 9 On solving, x = 5.
Statement 1 is sufficient.
Statement 2 : The total weight of the balls in the bag is between 1.05 kilogram and 1.35 kilogram
Each green ball weight 0.05kg and each red ball weight 0.1kg
Total number of balls : red + green = 0.1x + (0.5x + 9[0.5]) = 1.5x + 0.45kg
As per question stem, Weight of the bag can possibly lie between 1.05kg to 1.35kg, so possible options are 1.1 kg, 1.15 Kg, 1.2kg, 1.25kg, 1.30kg.
But for only value which is 1.2kg, the above equation gives solution.( Number of balls cannot be in decimal/fraction. So integer value is considered for x)
=> 1.5x + 0.45 = 1.2 => 1.5x = 0.75 => x = 5
Statement 2 is also sufficient.
So, answer is D.
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.