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Bunuel
A box contains 28 red balls, 20 green balls, 19 yellow balls, 13 blue balls, 11 white balls, and 9 black balls. What is the minimum number of balls that must be drawn from the box without replacement to guarantee that at least 15 balls of a single color will be drawn ?

A. 75
B. 76
C. 79
D. 84
E. 91

so as to get at least 15 balls of single color we need to take out
14 red,14 green, 14 yellow,13 blue ,11 white & 9 black ; total 75 ; picking 1 more ball will assure 15 balls of a single color; 76
IMO B

Yes, you are right. It should be B. I am learning this concept, but more often than not it goes over my head. :lol:
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To solve this, we have to take the worst case scenario.

Pick as many distinct balls as you can but never satisfy the condition to pick 15 balls of same colour.

So, we pick
14 red
14 green
14 yellow
13 blue
11 white
9 black balls
So, total of (14+14+14+13+11+9) = 75 balls.

Now, the bag has 1 ball of each of red, green and yellow colour.

No matter which ball we pick from this, we will have picked the 15th ball of the same colour for either red or green or yellow.

So, minimum of 76 balls will ensure that we have 15 balls of at least one of the colours.

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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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