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26 Feb 2025, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:10) correct
20%
(01:34)
wrong
based on 107
sessions
History
Date
Time
Result
Not Attempted Yet
A can do a work in 15 days and B can do the same work in 20 days. If they work together for 4 days, then the fraction of work that has left is:
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{5}\)
(C) \(\frac{1}{10}\)
(D) \(\frac{7}{15}\)
(E) \(\frac{8}{15}\)
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{5}\)
(C) \(\frac{1}{10}\)
(D) \(\frac{7}{15}\)
(E) \(\frac{8}{15}\)
Updated on: 26 Feb 2025, 01:49
Originally posted by ManifestDreamMBA on 26 Feb 2025, 01:38.
Last edited by ManifestDreamMBA on 26 Feb 2025, 01:49, edited 1 time in total.
Last edited by ManifestDreamMBA on 26 Feb 2025, 01:49, edited 1 time in total.
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Time required to do the work when both work together = 15*20/(15+20) = 60/7
They complete the 1 unit of work in 60/7 days
They complete in 4 days = 4*1/(60/7) = 7/15
Work left = 1-7/15 = 8/15
They complete the 1 unit of work in 60/7 days
They complete in 4 days = 4*1/(60/7) = 7/15
Work left = 1-7/15 = 8/15
Bunuel
26 Feb 2025, 01:41
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Bunuel
Related Video:
So we know that W/MT = Constant
A's 1 day work = 1/15
B's 1 day work = 1/20
1 day work of both = (1/15)+(1/20) =7/60
4 day's work = 4*(7/60) = 7/15
Remaining work = 1-(7/15) =8/15
Answer: Option E
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