atalpanditgmat wrote:
A certain box contains only blue (b), green (g) and red(r) marbles. If one marble is to be picked out from the box at random, which color marble is most likely to be picked?
(1)\(\frac{b}{(g+r)}>\frac{r}{(g+b)}\)
(2) g > b
From stimulus we know that there are only Blue, Green and Red marbles.
So the probability of being picked will be directly proportional to the the number.
If Green has the highest number then green will have the highest probability
If Red has the highest number then red will have the highest probability
If Blue has the highest number then blue will have the highest probability
(1)\(\frac{b}{(g+r)}>\frac{r}{(g+b)}\)
This tells us that ratio of blue to other two colors is higher than ratio of red to other two colors
Meaning that Blue is more in number than Red.
But we don't know the number of green
INSUFFICIENT
(2) g > b[/quote]
This tells us that Green is more than blue
But we do not know anything about Red
INSUFFICIENT
COMBINE
GREEN > BLUE>RED
SUFFICIENT
ANSWER IS C
The probability of green is highest and red is lowest.
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