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A certain calculator is able to display at most 10 digits, [#permalink]

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19 Dec 2004, 19:19

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A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?

A certain calculator is able to display at most 10 digits, [#permalink]

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24 Jul 2011, 15:35

A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?

(1) 105 < x < 108

(2) 3 < y < 6

Last edited by Bunuel on 11 Jul 2013, 02:17, edited 1 time in total.

statement 2 can have values either 4 or 5... which should generate a terminating decimal, whatever the value of x may be. so sufficient..

statement 1 can have values such as 106, 107... 107 when divided by 3.. will not generate a terminating #. whereas 106 when divided by 2 will generate a terminating #. so not sufficient.

A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?

(1) 105 < x < 108

(2) 3 < y < 6

From Stmt 1: if x = 106 and y = 2 then x/y can be displayed accurately However, if x = 106 and y = 3 then x/y cannot be displayed accurately

From Stmt 2: possible value of y = 4 and 5. Any number divided by either 4 or 5 will be either an integer or a terminating decimal series. Hence suff. B

Re: A certain calculator is able to display at most 10 digits, [#permalink]

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25 Feb 2014, 07:16

Hi guys, can any one explain how this question is answered. i understand that anything divided by 4 or 5 will either be a integer or a terminating decimal series, but how does this ensure that the total number of digits will not be more than 10?

Re: A certain calculator is able to display at most 10 digits, [#permalink]

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18 May 2014, 10:17

Ans should be B

Statement 1:

don't know about y-------insufficient

Statement 2: 3<y<6 means y could be 4 or 5

now, any three digit number can be written as (100x+10y+z)

as , 100 is divisible by 4 & 5 10 /4=2.5 & 10/5 =2 so we need to check for z.

check for last digit 1/4=0.25 , 2/4=0.5, 3/4 =0.75, 4/4=1, 5/4=1.25 , 6/4=1.5, 7/4= 1.75, 8/4=2, 9/4= 2.25 means Any number less than 1000 when divided by 4 will give at most 3 digits before decimal and 2 digits after decimal, so in total 5 digits.

Re: A certain calculator is able to display at most 10 digits, [#permalink]

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18 Feb 2016, 22:56

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Re: A certain calculator is able to display at most 10 digits, [#permalink]

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26 Apr 2016, 18:02

cpcalanoc wrote:

A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?

(1) 105 < x < 108

(2) 3 < y < 6

question actually asks: does y have a factor of 2 or 5?

1. nothing about y 2. sufficient. we know that y either has a factor of 2 or 5, so it will be a terminating decimal, and we know for sure that we can represent x/y accurately.