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A certain calculator is able to display at most 10 digits, [#permalink]
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19 Dec 2004, 19:19
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A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator? (1) 105 < x < 108 (2) 3 < y < 6
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Last edited by Bunuel on 16 Jan 2014, 04:16, edited 1 time in total.
Edited the question and added the OA.



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B is right for sure
from (2) y can be 4,5
while dividing by 4 there can be three remainders 1,2,3 so the result will end with
0.25, 0.5, 0.75
the same argumentation 1,2,3,4 possible digits after decimal point 0.2,0.4,0.6,0.8
So (1) is not necessary here.



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The concept for why B is the answer can be explained if you follow another post about terminating digits
http://www.gmatclub.com/phpbb/viewtopic.php?t=12372
Thanks for the information Gayathri  Learnt something today



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A certain calculator is able to display at most 10 digits, [#permalink]
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24 Jul 2011, 15:35
A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?
(1) 105 < x < 108
(2) 3 < y < 6
Last edited by Bunuel on 11 Jul 2013, 02:17, edited 1 time in total.
Added the OA.



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Re: DS  700 level  calculator [#permalink]
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24 Jul 2011, 16:06
i think B.
statement 2 can have values either 4 or 5... which should generate a terminating decimal, whatever the value of x may be. so sufficient..
statement 1 can have values such as 106, 107... 107 when divided by 3.. will not generate a terminating #. whereas 106 when divided by 2 will generate a terminating #. so not sufficient.



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Re: DS  700 level  calculator [#permalink]
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24 Jul 2011, 22:15
A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?
(1) 105 < x < 108
(2) 3 < y < 6
From Stmt 1: if x = 106 and y = 2 then x/y can be displayed accurately However, if x = 106 and y = 3 then x/y cannot be displayed accurately
From Stmt 2: possible value of y = 4 and 5. Any number divided by either 4 or 5 will be either an integer or a terminating decimal series. Hence suff. B



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Re: A certain calculator is able to display at most 10 digits, [#permalink]
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15 Jan 2014, 15:51
Q: Displayed accurately → Result fit within 10 digits
(1): Numerator x = 106 or 107 → Not given Denominator y Insufficient (2): Denominator y = 4 or 5 → Result fit within 10 digits Sufficient
Does it make sense?



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Re: A certain calculator is able to display at most 10 digits, [#permalink]
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25 Feb 2014, 07:16
Hi guys, can any one explain how this question is answered. i understand that anything divided by 4 or 5 will either be a integer or a terminating decimal series, but how does this ensure that the total number of digits will not be more than 10?



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Re: A certain calculator is able to display at most 10 digits, [#permalink]
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18 May 2014, 10:17
Ans should be B
Statement 1:
don't know about yinsufficient
Statement 2: 3<y<6 means y could be 4 or 5
now, any three digit number can be written as (100x+10y+z)
as , 100 is divisible by 4 & 5 10 /4=2.5 & 10/5 =2 so we need to check for z.
check for last digit 1/4=0.25 , 2/4=0.5, 3/4 =0.75, 4/4=1, 5/4=1.25 , 6/4=1.5, 7/4= 1.75, 8/4=2, 9/4= 2.25 means Any number less than 1000 when divided by 4 will give at most 3 digits before decimal and 2 digits after decimal, so in total 5 digits.
same applies with 5 also so sufficient



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Re: A certain calculator is able to display at most 10 digits, [#permalink]
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18 Feb 2016, 22:56
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Re: A certain calculator is able to display at most 10 digits, [#permalink]
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26 Apr 2016, 18:02
cpcalanoc wrote: A certain calculator is able to display at most 10 digits, so that any number with a total of more than 10 digits before and after the decimal point cannot be displayed accurately. If x and y are positive integers less than 1,000, can the result of dividing x by y be displayed accurately on the calculator?
(1) 105 < x < 108
(2) 3 < y < 6 question actually asks: does y have a factor of 2 or 5? 1. nothing about y 2. sufficient. we know that y either has a factor of 2 or 5, so it will be a terminating decimal, and we know for sure that we can represent x/y accurately.




Re: A certain calculator is able to display at most 10 digits,
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26 Apr 2016, 18:02







