Last visit was: 20 Nov 2025, 00:59 It is currently 20 Nov 2025, 00:59
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Antmavel
User avatar
Current Student
Joined: 13 Jun 2004
Last visit: 05 Apr 2014
Posts: 581
Own Kudos:
134
 [35]
Location: London, UK
Schools:Tuck'08
Posts: 581
Kudos: 134
 [35]
1
Kudos
Add Kudos
34
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,408
Own Kudos:
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,408
Kudos: 778,423
 [13]
7
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
User avatar
intr3pid
Joined: 05 Sep 2004
Last visit: 20 Sep 2004
Posts: 40
Own Kudos:
11
 [9]
Posts: 40
Kudos: 11
 [9]
6
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
General Discussion
User avatar
ywilfred
Joined: 07 Jul 2004
Last visit: 06 Mar 2012
Posts: 1,989
Own Kudos:
2,031
 [4]
Location: Singapore
Posts: 1,989
Kudos: 2,031
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Backsolving,

If sides are 7, vol=7^3=343
80%= 274.4, 85%=291.55
so vol above water, between 68.6 and 51.45 -->too big

If side are 4, vol = 64
80%=51.2, 85%=54.4
vol above water between 12.8 and 9.6

So 4 should be the answer.
Check option C,
If sides are 5, vol = 125
80%= 100, .85%=106.25
vol above water bwtween 18.75-25


(Sides are 4 cubic centimeters)
User avatar
srijay007
Joined: 05 May 2004
Last visit: 05 Jul 2006
Posts: 337
Own Kudos:
Location: San Jose, CA
Posts: 337
Kudos: 240
Kudos
Add Kudos
Bookmarks
Bookmark this Post
if L be the side
using data1
L^2*0.2*L=12 or L=60^1/3 = 4 appx
using data2
L^2*0.15*L=16 or L=106^1/3 = 4+ appx (but less than 5)

Hence A is safest bet!
User avatar
Antmavel
User avatar
Current Student
Joined: 13 Jun 2004
Last visit: 05 Apr 2014
Posts: 581
Own Kudos:
134
 [3]
Location: London, UK
Schools:Tuck'08
Posts: 581
Kudos: 134
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Best way to approach this problem is to plug in the answers since the
answers give us the side of the cube.

If we start with the middle choice, C, then we have a cube with
side 7. If the cube has a side of 7 then it will have a volume of 343. We are told that between 80 and 85% of the volume is below the surface of the water, which means that between 15 and 20% of the volume is above the surface.

If the volume of the cube is 343 then 20% is about 68 and 15% is about
51. Neither of these numbers is between the 12 and 16 cubic centimeters that are supposed to be above water, so clearly this can’t be the answer.

Since the numbers are too large with need to trysomething smaller. Pick one of the smaller choices and try again. Then you'll find it :wink:

I can see by the number of good answers to my several daily problems that everybody is sharp and ready for the GMAT :)
User avatar
iwillcrackgmat
Joined: 22 Jan 2012
Last visit: 01 Mar 2015
Posts: 61
Own Kudos:
518
 [1]
Given Kudos: 9
Location: India
Concentration: General Management, Technology
GPA: 3.3
WE:Engineering (Consulting)
Posts: 61
Kudos: 518
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
let side = a
80% underwater => 16 cc

Therefore , 20%(V) = 16, or a^3 = 80 cc. => a = 4.31,

If 85% underwater => 12 cc above water:

Thus, 15%(V) = 12, or a^3 = 80 cc, a = 4.31

So C is the best answer
User avatar
SVaidyaraman
Joined: 17 Dec 2012
Last visit: 11 Jul 2025
Posts: 576
Own Kudos:
Given Kudos: 20
Location: India
Expert
Expert reply
Posts: 576
Kudos: 1,795
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Antmavel
A certain cube floating in a bucket of water has between 80 and 85 percent of its volume below the surface of the water. If between 12 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately

A. 4
B. 5
C. 7
D. 8
E. 9

1. 80% below water implies 20 % above water. 85% below water implies 15% above water
2. It is also given between 12 and 16 cu.cm above water.
3. So we can equate 20% to 16 cu.cm or 15% to 12 cu.cm. In either case 100% volume is 80 cu.cm
4. So length is cube root of 80 .

Choice A is the closest.
avatar
madn800
Joined: 07 May 2013
Last visit: 11 Aug 2014
Posts: 67
Own Kudos:
Given Kudos: 1
Posts: 67
Kudos: 66
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel, how did you find value of cube root 10. How is it possible to compute such a value under exam conditions.
User avatar
SVaidyaraman
Joined: 17 Dec 2012
Last visit: 11 Jul 2025
Posts: 576
Own Kudos:
1,795
 [3]
Given Kudos: 20
Location: India
Expert
Expert reply
Posts: 576
Kudos: 1,795
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
madn800
Bunuel, how did you find value of cube root 10. How is it possible to compute such a value under exam conditions.

Hi,

Let us say you want to find out the cube root of 10. The cube of which number is immediately below 10? It is 2 because 2^3=8. Or you can see the cube of which number is immediately above 10? It is 3 because 3^3=27. So the cube root of 10 is between 2 and 3. You can further make it finer by seeing whether it is closer to 2^3 or 3^3.
User avatar
gmatprav
Joined: 25 Oct 2013
Last visit: 19 Nov 2015
Posts: 111
Own Kudos:
Given Kudos: 55
Posts: 111
Kudos: 185
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Volume of cube of side s is s^3.

80% under water is 20% above water this implies

\(\frac{20}{100}*s^3 = 16\)

\(s^3=80\)

85% under water is 15% above water this implies

\(\frac{15}{100}*s^3 = 12\)

\(s^3 = 80\)

Now going to the answers if s=4 \(s^3 = 64\). closer to 80 a possible answer.
if s=5 \(s^3 = 125\). too far from 80. hence A is answer.
User avatar
kundankshrivastava
Joined: 14 May 2014
Last visit: 18 Oct 2014
Posts: 35
Own Kudos:
Given Kudos: 1
Posts: 35
Kudos: 170
Kudos
Add Kudos
Bookmarks
Bookmark this Post
80 % below the surface means 20 % above the surface
85 % below the surface means 15% above the surface

If volume is V then 20% of V = 16 cubic meter => V = 80 cubic cm

or ,
If Volume is V then 15% of V = 12 cubic meter => =V = 80 cubic cm

Side of cube = cubic root (80)

we have 4^3 = 64 and 5^3 = 125
64 < 80 <125
4 < side <5
as 80 is nearer to 64 than to 125

hence side is approx 4 , Answer is A
avatar
PareshGmat
Joined: 27 Dec 2012
Last visit: 10 Jul 2016
Posts: 1,534
Own Kudos:
Given Kudos: 193
Status:The Best Or Nothing
Location: India
Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,534
Kudos: 8,102
Kudos
Add Kudos
Bookmarks
Bookmark this Post
iwillcrackgmat
let side = a
80% underwater => 16 cc

Therefore , 20%(V) = 16, or a^3 = 80 cc. => a = 4.31,

If 85% underwater => 12 cc above water:

Thus, 15%(V) = 12, or a^3 = 80 cc, a = 4.31

So A is the best answer


Correcting.. A is the answer
avatar
Akuthiala
Joined: 23 Jun 2016
Last visit: 18 Oct 2016
Posts: 34
Own Kudos:
Given Kudos: 13
Posts: 34
Kudos: 10
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Use Plug in numbers startegy

Start with B
if side is 5 then volume is 125 20% of 125 = 25 (wrong since the range is 12-16) so the side must be smaller and 15% = 18.75 outside range of 12-16

Hence answer is A

We can double check if we have time on GMAT

if aside is 4 vol is 64 20% is 12.8 and 15% 9.6 (within range)
avatar
RR88
Joined: 18 Oct 2016
Last visit: 16 Oct 2019
Posts: 108
Own Kudos:
Given Kudos: 91
Location: India
WE:Engineering (Energy)
Posts: 108
Kudos: 149
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel,
Will be glad to receive your take on this approach.

Alternate Method

Option A)

Volume of cube outside water can be written as : side * side * (A fraction of side) = (side)^2 * (A fraction of side)
Hence, volume of cube outside water should be a multiple of a perfect square.

Given - Possible volume of cube outside water ranges from 12 to 16; and by prime factorizing the values from 12 to 16 we can find only 16 fits aforementioned criteria. As, 16 = 4 * 4 * 1 = 4^2 * 1 = side^2 * (A fraction of side).

Hence, side = 4cm
User avatar
Cez005
Joined: 13 Dec 2013
Last visit: 11 Feb 2020
Posts: 95
Own Kudos:
Given Kudos: 122
Location: United States (NY)
Concentration: General Management, International Business
GMAT 1: 710 Q46 V41
GMAT 2: 720 Q48 V40
GPA: 4
WE:Consulting (Consulting)
Products:
GMAT 2: 720 Q48 V40
Posts: 95
Kudos: 145
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Taking 14 as the number of cubic cm above water, and 80% as the percentage of the volume below water, the total volume of the cube is 14*5=70.
The cube root of 70 is much closer to 4 than 5, therefore 4 is the answer.
User avatar
prateekchugh
Joined: 05 Aug 2017
Last visit: 27 Sep 2021
Posts: 358
Own Kudos:
Given Kudos: 277
Location: India
Concentration: Strategy, Marketing
WE:Engineering (Energy)
Posts: 358
Kudos: 560
Kudos
Add Kudos
Bookmarks
Bookmark this Post
A certain cube floating in a bucket of water has between 80 and 85 percent of its volume below the surface of the water. If between 12 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately

80%<Volume below the surface<85%; 20%<Volume above the surface<15%
12<Volume above the surface<16;

\(\frac{20}{100}*v=12;\frac{15}{100}*v=16\)
v=60 and v=106.6
60<Total volume<106.6
60<a^3<106.6
If a=4; V=64....Between the above range
If a=5; V=125....beyond the range

Answer is 4


A. 4
B. 5
C. 7
D. 8
E. 9
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,593
Own Kudos:
Posts: 38,593
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105408 posts
Tuck School Moderator
805 posts