Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jan 1610:00 AM EST
-12:00 PM EST
The Target Test Prep team is proud to introduce GMAT OnDemand, a video course created by Scott Woodbury-Stewart, founder and CEO, designed to provide you with everything you need to master the GMAT and achieve your score goals.
Jan 1610:00 AM PST
-11:00 AM PST
Meet Kseniia, a former Public Relations Head at Google in Russia, whose inspiring journey defied the odds and landed her admissions to Wharton, Chicago Booth, and Yale SOM.- Jan 15
07:30 AM PST
-08:30 AM PST
Studying for the GMAT can feel like a long journey, but having the right plan can keep you on track. In this live session, Julia, who scored a perfect 805, will share her step-by-step study plan for 2025. Join for help with key strategies and tips... - Jan 17
10:00 AM PST
-11:00 AM PST
Keshav who scored 99 percentile with near-perfect quant score shares his strategies and techniques to identify and overcome the weaknesses in his GMAT preparation. Learn the preparation tips and study strategies that worked for him. 
Jan 1805:30 AM PST
-07:30 AM PST
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.- Jan 18
10:00 AM PST
-11:00 AM PST
In this video, we talked to Rishi, an ambitious Indian student who successfully secured admission into HEC Paris and ESSEC Business School, two of the top Masters in Management (MiM) programs in Europe. 
Jan 1811:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Jan 19
11:00 AM IST
-01:00 PM IST
Attend this session to evaluate your current skill level, learn process skills, and solve through tough Arithmetic questions 
Jan 1911:30 AM EST
-12:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
15 Jun 2020, 04:04
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
92% (01:09) correct
8%
(01:26)
wrong
based on 225
sessions
History
Date
Time
Result
Not Attempted Yet
A certain language school has two classes for children. Is the range of ages, in years, of the children in the first class equal to the range of ages, in years, of the children in the second class?
(1) In each class, the number of children is 18 and the age of the youngest child is 8 years.
(2) In each class, the average (arithmetic mean) age of the children is 10 years.
(1) In each class, the number of children is 18 and the age of the youngest child is 8 years.
(2) In each class, the average (arithmetic mean) age of the children is 10 years.
Updated on: 15 Jun 2020, 05:04
Originally posted by RaghavKhanna on 15 Jun 2020, 04:21.
Last edited by RaghavKhanna on 15 Jun 2020, 05:04, edited 1 time in total.
Last edited by RaghavKhanna on 15 Jun 2020, 05:04, edited 1 time in total.
Kudos
Bookmarks
Range of children in a class = Maximum age of a child - Minimum age of a child
To evaluate: Range 1 = Range 2
St. 1:
Minimum age is given, but no information about the maximum age in each class.
=> St. 1 is insufficient.
St. 2:
Only information about the mean.
We can't determine the max and min values in each class.
=> St. 2 is insufficient.
St. 1 and St. 2 together:
Sum of ages of all students in each class = 18*10 = 180 years
Age of youngest student in each class = 8
=> Sum of ages of other 17 students in each class = 172 years
We still can't find the age of the eldest student as any there could be many cases in which the sum of ages of 17 students equals 172 years.
=> Both 1 and 2 together are also insufficient.
=> Answer: E
To evaluate: Range 1 = Range 2
St. 1:
Minimum age is given, but no information about the maximum age in each class.
=> St. 1 is insufficient.
St. 2:
Only information about the mean.
We can't determine the max and min values in each class.
=> St. 2 is insufficient.
St. 1 and St. 2 together:
Sum of ages of all students in each class = 18*10 = 180 years
Age of youngest student in each class = 8
=> Sum of ages of other 17 students in each class = 172 years
We still can't find the age of the eldest student as any there could be many cases in which the sum of ages of 17 students equals 172 years.
=> Both 1 and 2 together are also insufficient.
=> Answer: E
15 Jun 2020, 04:57
Kudos
Bookmarks
Statement 1 :
Here only the age of youngest child is given, i.e., 8 years.
And the total number of children is 18.
From here we are unable to determine the range of ages of each class.
Thus insufficient.
Statement 2:
Here the average age of the children in given, i.e., 10 years.
Which is just insufficient to calculate the range of the ages.
Combining both statement, (for each class)
Here we can get the age of the eldest child, say X.
Now, (8 + X) / 2 = 10,
Or, X = 12,
Now the range will be 12 - 8 = 4.
Combining works.
Thus Sufficient.
IMO ans is C.
Here only the age of youngest child is given, i.e., 8 years.
And the total number of children is 18.
From here we are unable to determine the range of ages of each class.
Thus insufficient.
Statement 2:
Here the average age of the children in given, i.e., 10 years.
Which is just insufficient to calculate the range of the ages.
Combining both statement, (for each class)
Here we can get the age of the eldest child, say X.
Now, (8 + X) / 2 = 10,
Or, X = 12,
Now the range will be 12 - 8 = 4.
Combining works.
Thus Sufficient.
IMO ans is C.
