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26 Mar 2018, 10:44
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Solution:
Given:
- • Cost of a single jack = 19c
• Cost of a single marble = 25c
• Total money = $10
Working out:
We need to find the number of ways in which a person can buy jacks and marbles with $10.
Let us assume that the number of jacks = j, and the number of marbles = m.
- • Thus, total amount spent = 19*j + 25*m
• This amount is equal to $10 or 10*100 = 1000 cents
• Thus, we can write: \(19j + 25m = 1000\)
Dividing both the sides of this equation by 25, we get:
- • \(19j/25 + m = 40\)
Since m is an integer, \(19j/25\) should also be an integer.
Thus, j has to be a multiple of 25.
Multiples of 25 are: 0, 25, 50,75,100…
Putting these values of j, let us try to find the different possible combinations:
Hence, there are only 3 possible ways in which the items can be bought using $10.
Answer: Option D
rvgmat12
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07 Nov 2021, 03:11
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19x + 25y = 1000
50, 2
25, 21
0, 40
3 ways
D
50, 2
25, 21
0, 40
3 ways
D
30 Apr 2025, 04:55
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