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Let's assume the number of Paperbacks to be 'x' and the number of hardcovers to be 'y'.
So, the total number of books would be:
x+y=120 -- Eqn. 1

Now, for 'x' number of paperbacks costing him $1 each, his selling price according to the question would become '3x' and hence the profit would be '2x'.
Likewise, the selling price of hardcovers would become '4y' and the profit would be '3y'.
Now, we've been given that the profit is 300 i.e.
2x+3y=300 -- Eqn 2

On solving the above two equations, you'll get x and y to be 60 each.

Hope it helps :)
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Given

    • A certain used-book dealer sells paperback books at 3 times dealer's cost and hardback books at 4 times dealer's cost.
    • The dealer sold a total of 120 books, each of which had cost the dealer $1.
    • If the gross profit (sales revenue minus dealer's cost) on the sale of all of these books was $300


To Find

    • The number of paperbacks sold.

Approach and Working Out

    • Let’s assume all the books are hardbacks.
      o Total profit would have been 120 × 3 = 360.

    • But his profit is 360-300 = 60 less.

    • For each paperback the profile is 1 less.

    • Total number of paperback books = 60/1 = 60

Correct Answer: Option B
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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