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Re: A clothing retailer bought 2 shipments of equal numbers of dresses at [#permalink]
Bunuel wrote:

CHALLENGE QUESTION:



A clothing retailer bought 2 shipments of equal numbers of dresses at the same price. When the first shipment was sold in its entirety at $70 per dress, it generated $1,600 in profits. When the retailer sold the second shipment in its entirety at $90 per dress, it generated $2,400 in profits. What was the total number of dresses in both shipments?

(A) 40
(B) 50
(C) 60
(D) 80
(E) 100


Dresses in Shipment 1 = S1 = n
Dresses in Shipment 2 = S2 = n

Cost per shipment = C

Profit = Revnune - Cost

For S1: 1600 = 70n - C

For S2: 2400 = 90n - C

Note: The cost of both shipments is the same as both shipment are identical of terms of number and cost per dress.

Subtract equations

800 = 20n...........n =40 dress per shipment

Then Toyla shipment = 80 dresses

Answer: D
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Re: A clothing retailer bought 2 shipments of equal numbers of dresses at [#permalink]
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Bunuel wrote:

CHALLENGE QUESTION:



A clothing retailer bought 2 shipments of equal numbers of dresses at the same price. When the first shipment was sold in its entirety at $70 per dress, it generated $1,600 in profits. When the retailer sold the second shipment in its entirety at $90 per dress, it generated $2,400 in profits. What was the total number of dresses in both shipments?

(A) 40
(B) 50
(C) 60
(D) 80
(E) 100


Since the number of dresses and cost price is the same in both,
Simply note that an extra $20 charge ($90 sale price instead of $70 sale price) led to an extra profit of $800 (= 2400 - 1600).
So there must have been 800/20 = 40 dresses in one lot.
This means a total of 80 dresses.

Answer (D)
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Re: A clothing retailer bought 2 shipments of equal numbers of dresses at [#permalink]
Let No. of dresses be n and original cost per dress be x

Then 70n=x+1600
90n=x+2400

Solving gives n=40

Thus total dresses is 2n=80

Ans:D
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Re: A clothing retailer bought 2 shipments of equal numbers of dresses at [#permalink]
Given: A clothing retailer bought 2 shipments of equal numbers of dresses at the same price. When the first shipment was sold in its entirety at $70 per dress, it generated $1,600 in profits. When the retailer sold the second shipment in its entirety at $90 per dress, it generated $2,400 in profits.

Asked: What was the total number of dresses in both shipments?

Let the total number of dresses be 2x.

First shipment:-
SP = $70x
Profits= $1600
CP = $70x - $1600

Second shipment: -
SP = $90x
Profits = $2400
CP = $90x - $2400

Since both shipments were purchased at same price

CP = $70x - $1600 = $90x - $2400
$20x = $800
x = 40
2x = 80

IMO D
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Re: A clothing retailer bought 2 shipments of equal numbers of dresses at [#permalink]
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Re: A clothing retailer bought 2 shipments of equal numbers of dresses at [#permalink]
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