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Kritisood
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According to its language two different teams are ro be made hence the answer should be 65 in that case

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6p2× 7c3 =30×35=1050
P because of different positions and c because of same positions

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Company will select 2 of 6 = 6C2 =15,
then it will put those selected in 2 different position - it can be done in 2! = 2 ways.
They have to select 3 of 7 = 7C3 = 35,
then it will put those selected in same postion, can be done only in 1 way.

Therefore, number of ways in which they can fill a position is 15 x 2 x 35 =1050
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Kritisood
A co. will select 2 of the 6 candidates available to work in 2 different positions in the Tech team and 3 of the 7 candidates to work in the same position in the HR team. Find the number of ways in which the company can fill the position?

A.57
B. 65
C. 128
D. 256
E. 1050

The key to solving the probel is understanding the fact that chosing of the team is not independent events but rather these are continous events

The total possibilities being
6c2*7c3*2! => 15*35*2
=> 1050
Therefore IMO E
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Here's the video solution:


Smart Prep (Tutor)
Kritisood
A co. will select 2 of the 6 candidates available to work in 2 different positions in the Tech team and 3 of the 7 candidates to work in the same position in the HR team. Find the number of ways in which the company can fill the position?

A.57
B. 65
C. 128
D. 256
E. 1050

Hi, I cant understand the language of this question nor the solution. could someone help validate?
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