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Solution



Given:
    • A cockroach population doubles in every 3 days

To find:
    • The percentage increase in the cockroach population in 30 days

Approach and Working:
If we assume that initially (at the beginning of 30 days) the population was p, then
    • Population after \(3 * 1\) days = \(p * 2^1\)
    • Population after \(3 * 2\) days = \(p * 2^2\)
    • Population after \(3 * 3\) days = \(p * 2^3\)
Similarly, we can say
    • Population after \(3 * 10\) days = \(p * 2^{10}\) = 1024p
    • Therefore, the percentage increase = \(\frac{(1024p – p)}{p} * 100\) = 102300%

Hence, the correct answer is option D.

Answer: D
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A cockroach population doubles every 3 days. In 30 days, by what percent would a cockroach population increase?

(A) 900%
(B) 1,000%
(C) 9,999%
(D) 102,300%
(E) 102,400%

Doubling activities will be taken place for 10 times as cockroach doubles every 3 days. This can be expressed as follows:

no. of cockroach * \(2^{10}\)
=C*1024
=1024C..........................C for cockroach

Percentage change in Cockroach ={ (1024C - C)/C}*100
= 1023*100
= 102300%, which is option D.
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egmat in this question I tried number picking and picked "2", it did not work.

2^10 = 1024, therefore 1024-2/2*100 = wrong answer

why doesnt this approach works ?
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hero_with_1000_faces
egmat in this question I tried number picking and picked "2", it did not work.

2^10 = 1024, therefore 1024-2/2*100 = wrong answer

why doesnt this approach works ?

hero_with_1000_faces

So what you have assumed is that the cockroach population was 2. It doubled every 3 days
and on the 30th day, it would have doubled for the 10th time. The population would be 2048
on the 30th day.

So, the percentage change in the number of cockroaches will be \(\frac{2048 - 2}{2}\) or \(1023\)%

Hope this helps you!
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pushpitkc

Thanks Man, silly mistake :D
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Doubles ever 3 days, and 30 days is 3 * 10

Let OG number be x

Increased number after 30 days (x)*(2)^10 [it is doubled 10 times in 30 days]

Percent increase ends up being (2^10 - 1) * 100 [you can take x outside and it cancels out in the numerator and denominator]

which is (2^5 - 1) (2^5 + 1) * 100

which is 31*33*100

which is 102300
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Assume no of cockroaches on day = 1
After 3 days count will be = 1x 2 = 2
Similarly after 30 days (every 3 days doubles) so 1 x 1024 ( as 2 exponent 10 times will be the increase in 30 days)
Percentage increase = 1024 - 1 = 1023 > 1023 / 1 x 100 = 102300 % is the answer
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