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A collection of books went on sale, 1/6 of which were sold at $3.50 ea

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A collection of books went on sale, 1/6 of which were sold at $3.50 ea  [#permalink]

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New post 04 Jan 2018, 23:36
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

90% (02:48) correct 10% (02:30) wrong based on 46 sessions

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A collection of books went on sale, 1/6 of which were sold at $3.50 ea  [#permalink]

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New post 05 Jan 2018, 01:21
Bunuel wrote:
A collection of books went on sale, 1/6 of which were sold at $3.50 each and 3/5 were sold at $5 each. If the number of unsold books is 28, what is the total revenue received for the books that were sold?

A. $158
B. $248
C. $350
D. $430
E. $460


Let the total number of books be x.

\(x - \frac{x}{6} - \frac{3x}{5} = 28\) --> \(\frac{30x - 5x - 18x}{30} = 28\) --> \(\frac{7x}{30} = 28\) --> \(x = 4*30 = 120\)

Since \(\frac{1}{6}\)th of books were sold at 3.50$, \(\frac{1}{6}*120*3.50 = 70\) is the revenue from the sales.
Similarly, \(\frac{3}{5}\)th of the books were sold at 5$ each, \(\frac{3}{5}*120*5 = 360\) is the revenue from the sales.

Therefore, total revenue from the sales of these books is 70+360 = 430(Option D)
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Re: A collection of books went on sale, 1/6 of which were sold at $3.50 ea  [#permalink]

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New post 05 Jan 2018, 05:43
Bunuel wrote:
A collection of books went on sale, 1/6 of which were sold at $3.50 each and 3/5 were sold at $5 each. If the number of unsold books is 28, what is the total revenue received for the books that were sold?

A. $158
B. $248
C. $350
D. $430
E. $460


1- (1/6) - (3/5) = 7/30

i.e. 7/30 of total books = 28

total books = 120

Revenue = (1/6)*120*3.5 + (3/5)*120*5 = 70+360 = 430

Answer: Option D
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Re: A collection of books went on sale, 1/6 of which were sold at $3.50 ea   [#permalink] 05 Jan 2018, 05:43
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