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# A committee of three is to be chosen from six. How many unique committ

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A committee of three is to be chosen from six. How many unique committ  [#permalink]

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17 Aug 2017, 01:09
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Difficulty:

5% (low)

Question Stats:

77% (00:28) correct 23% (00:30) wrong based on 139 sessions

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A committee of three is to be chosen from six. How many unique committees result?

(A) 20
(B) 40
(C) 60
(D) 105
(E) 120

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Posts: 126
Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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17 Aug 2017, 04:15
6C3 = 20

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A committee of three is to be chosen from six. How many unique committ  [#permalink]

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Updated on: 17 Aug 2017, 12:00
kunalsinghNS wrote:
6C3 = 20

is it 20?

6C1 * 5C1 * 4C1 =120

Originally posted by rocko911 on 17 Aug 2017, 09:46.
Last edited by rocko911 on 17 Aug 2017, 12:00, edited 1 time in total.
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A committee of three is to be chosen from six. How many unique committ  [#permalink]

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17 Aug 2017, 10:54
6 x 5 x 4 = 120 = E

6 members. 3 slots. Members can't be selected multiple times.
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Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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17 Aug 2017, 11:52
1
Imo it should 6p3... I.e. 120.

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A committee of three is to be chosen from six. How many unique committ  [#permalink]

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Updated on: 17 Aug 2017, 20:15
rocko911 wrote:
kunalsinghNS wrote:
6C3 = 20

is it 20?

6C1 * 5C1 * 4C1 =120

What 6*4*3 does that it eliminates the repitations of a member that is selected in the previous slots in the committee but

6C3 tells all possible unique combinations

OA !

Originally posted by kunalsinghNS on 17 Aug 2017, 19:33.
Last edited by kunalsinghNS on 17 Aug 2017, 20:15, edited 1 time in total.
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Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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17 Aug 2017, 19:44
Is it 20?
6c3?
how is it 6p3? thanks
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Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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17 Aug 2017, 19:52
Example take a committee of 2 to be chosen from 4
A,B,C,D be members
Then AB BC CD AD BD AC are the
Unique committees
That is 4C2=6.
Similarly 6C3 there and it is 20../

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Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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22 Aug 2017, 16:47
Bunuel wrote:
A committee of three is to be chosen from six. How many unique committees result?

(A) 20
(B) 40
(C) 60
(D) 105
(E) 120

Because the order of selection doesn’t matter, this is a combination problem. The number of ways to select 3 people from 6 is 6C3 = 6!/[3!(6-3)!] = (6 x 5 x 4)/3! = (6 x 5 x 4)/(3 x 2) = 20.

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A committee of three is to be chosen from six. How many unique committ  [#permalink]

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Updated on: 14 Sep 2017, 06:10
Quote:
A committee of three is to be chosen from six. How many unique committees result?

(A) 20
(B) 40
(C) 60
(D) 105
(E) 120

6*5*4*3!/(3!*3!)= 20
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Originally posted by HUNTdGMAT on 23 Aug 2017, 00:00.
Last edited by HUNTdGMAT on 14 Sep 2017, 06:10, edited 2 times in total.
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Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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24 Aug 2017, 04:34
6C3
Choice-A
I consider it below 500 Level Question
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Re: A committee of three is to be chosen from six. How many unique committ  [#permalink]

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04 Nov 2018, 07:39
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Re: A committee of three is to be chosen from six. How many unique committ   [#permalink] 04 Nov 2018, 07:39
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