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A Container contains ‘X’ Liters of Milk. A thief stole 50

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A Container contains ‘X’ Liters of Milk. A thief stole 50  [#permalink]

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New post 18 Apr 2019, 02:45
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D
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Difficulty:

  55% (hard)

Question Stats:

58% (02:21) correct 42% (02:40) wrong based on 59 sessions

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A Container contains ‘X’ Liters of Milk. A thief stole 50 Liters of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus Milk in the container is only ‘X-122’ liters. Then what is the quantity of water in the final mixture?
a. 250 Liter
b. 124 Liter
c. 128 Liter
d. 122 Liter
e. 150 liter

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Re: A Container contains ‘X’ Liters of Milk. A thief stole 50  [#permalink]

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New post 18 Apr 2019, 07:33
3
1
Total container - Milk amount = water amount
X - (X-122) = 122.

It is an easy, but tricky ... started with complicated yet useless information.
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Re: A Container contains ‘X’ Liters of Milk. A thief stole 50  [#permalink]

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New post 23 Apr 2019, 20:07
jackfr2 wrote:
A Container contains ‘X’ Liters of Milk. A thief stole 50 Liters of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus Milk in the container is only ‘X-122’ liters. Then what is the quantity of water in the final mixture?
a. 250 Liter
b. 124 Liter
c. 128 Liter
d. 122 Liter
e. 150 liter

Posted from my mobile device



Since the thief always replaces the same amount of liquid every time, the final mixture is X liters as well. If there were X - 122 liters of milk after the third time, then there will be X - (X - 122) = 122 liters of water in the final mixture.

Answer: D
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Re: A Container contains ‘X’ Liters of Milk. A thief stole 50   [#permalink] 23 Apr 2019, 20:07
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A Container contains ‘X’ Liters of Milk. A thief stole 50

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