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A delivery truck starts on its route with a load of goods weighing T

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Bunuel
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A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  22 May 2020, 06:17
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A delivery truck starts on its route with a load of goods weighing T tons. At each of its first 4 stops, 1/2 of the weight of the goods still on the truck is unloaded. After the 4th stop, what is the weight, in tons, of the goods still on the truck?

A. 15T/16

B. T/4

C. T/6

D. T/8

E. T/16


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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  22 May 2020, 06:24
After stop 1: T/2
After stop 2: T/4
After stop 3: T/8
After stop 4: T/16
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Batman117
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  22 May 2020, 07:16
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For such kind of questions we can use formula of 2^n
Where n is number of action.
As we have to identify after 4th unloading
It will be 1/2^4 =1/16

Same if they have asked for after 6th unloading,just put n=6.

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BrentGMATPrepNow
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  22 May 2020, 07:37
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Bunuel wrote:
A delivery truck starts on its route with a load of goods weighing T tons. At each of its first 4 stops, 1/2 of the weight of the goods still on the truck is unloaded. After the 4th stop, what is the weight, in tons, of the goods still on the truck?

A. 15T/16

B. T/4

C. T/6

D. T/8

E. T/16
PS21183


If half the weight is REMOVED, then half the weight REMAINS

Initially, weight = T (tons)
After 1 stop: weight remaining = (1/2)T
After 2 stops: weight remaining = (1/2)(1/2)T
After 3 stops: weight remaining = (1/2)(1/2)(1/2)T
After 4 stops: weight remaining = (1/2)(1/2)(1/2)(1/2)T = (1/16)T = T/16

Answer: E

Cheers,
Brent
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Abhishek009
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  22 May 2020, 08:05
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Bunuel wrote:
A delivery truck starts on its route with a load of goods weighing T tons. At each of its first 4 stops, 1/2 of the weight of the goods still on the truck is unloaded. After the 4th stop, what is the weight, in tons, of the goods still on the truck?

A. 15T/16

B. T/4

C. T/6

D. T/8

E. T/16


PS21183


Let total weight T = 16

Load unloaded on 1st stop is 8 ; Load left = 8
Load unloaded on 2nd stop is 4 ; Load left = 4
Load unloaded on 3rd stop is 2 ; Load left = 2
Load unloaded on 4th stop is 1 ; Load left = 1

Hence, Load left on the truck is \(\frac{1}{16} = \frac{T}{16}\), Answer must be (E)
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Kimberly77
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  26 Jan 2023, 03:31
BrentGMATPrepNow wrote:
Bunuel wrote:
A delivery truck starts on its route with a load of goods weighing T tons. At each of its first 4 stops, 1/2 of the weight of the goods still on the truck is unloaded. After the 4th stop, what is the weight, in tons, of the goods still on the truck?

A. 15T/16

B. T/4

C. T/6

D. T/8

E. T/16
PS21183


If half the weight is REMOVED, then half the weight REMAINS

Initially, weight = T (tons)
After 1 stop: weight remaining = (1/2)T
After 2 stops: weight remaining = (1/2)(1/2)T
After 3 stops: weight remaining = (1/2)(1/2)(1/2)T
After 4 stops: weight remaining = (1/2)(1/2)(1/2)(1/2)T = (1/16)T = T/16

Answer: E

Cheers,
Brent


Hi BrentGMATPrepNow, when using number 20 testing, I end up with 20> 10> 5 > 2.5> 1.25/20 ?
Wondering why it only work with 16 only? Could you help? Thanks
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BrentGMATPrepNow
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  26 Jan 2023, 15:21
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Kimberly77 wrote:
BrentGMATPrepNow wrote:
Bunuel wrote:
A delivery truck starts on its route with a load of goods weighing T tons. At each of its first 4 stops, 1/2 of the weight of the goods still on the truck is unloaded. After the 4th stop, what is the weight, in tons, of the goods still on the truck?

A. 15T/16

B. T/4

C. T/6

D. T/8

E. T/16
PS21183


If half the weight is REMOVED, then half the weight REMAINS

Initially, weight = T (tons)
After 1 stop: weight remaining = (1/2)T
After 2 stops: weight remaining = (1/2)(1/2)T
After 3 stops: weight remaining = (1/2)(1/2)(1/2)T
After 4 stops: weight remaining = (1/2)(1/2)(1/2)(1/2)T = (1/16)T = T/16

Answer: E

Cheers,
Brent


Hi BrentGMATPrepNow, when using number 20 testing, I end up with 20> 10> 5 > 2.5> 1.25/20 ?
Wondering why it only work with 16 only? Could you help? Thanks


I believe you are using the input-output approach.
Am I right?

If so, you can use ANY values you want.
If T = 20 (tons), then the answer to our question is 1.25 tons of goods remaining (NOT 1.25/20) .
So now we'll take each answer choice, and INPUT T = 20, to see if we get an OUTPUT of 1.25

If you do this, you will see that none of the first four options work, but...

E) T/16 = 20/16 = 1.25. Perfect!!
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Kimberly77
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  01 Feb 2023, 12:48
Thanks BrentGMATPrepNow, make sense. However why is it when testing with 16 : 8 > 4> 2>1 we have 1/16=T/16.
However with 20, 10> 5 > 2.5> 1.25/20 can't/doesn't follow the same way?
Thanks Brent
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BrentGMATPrepNow
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  02 Feb 2023, 17:09
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Kimberly77 wrote:
Thanks BrentGMATPrepNow, make sense. However why is it when testing with 16 : 8 > 4> 2>1 we have 1/16=T/16.
However with 20, 10> 5 > 2.5> 1.25/20 can't/doesn't follow the same way?
Thanks Brent


Sorry, but I answered that question in my last post.
Please read it carefully.
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Kimberly77
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  04 Feb 2023, 12:15
BrentGMATPrepNow wrote:
Kimberly77 wrote:
Thanks BrentGMATPrepNow, make sense. However why is it when testing with 16 : 8 > 4> 2>1 we have 1/16=T/16.
However with 20, 10> 5 > 2.5> 1.25/20 can't/doesn't follow the same way?
Thanks Brent


Sorry, but I answered that question in my last post.
Please read it carefully.


Hi BrentGMATPrepNow, think I get it now. Is below understanding correct?

To clarify so when using using 16 : 8 > 4> 2>1 we have T/16 > 16/16=1
When using 20, 10> 5 > 2.5> 1.25. Therefore T/16 > 20/16=1.25

Thanks Brent
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BrentGMATPrepNow
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  05 Feb 2023, 07:56
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Kimberly77 wrote:
BrentGMATPrepNow wrote:
Kimberly77 wrote:
Thanks BrentGMATPrepNow, make sense. However why is it when testing with 16 : 8 > 4> 2>1 we have 1/16=T/16.
However with 20, 10> 5 > 2.5> 1.25/20 can't/doesn't follow the same way?
Thanks Brent


Sorry, but I answered that question in my last post.
Please read it carefully.


Hi BrentGMATPrepNow, think I get it now. Is below understanding correct?

To clarify so when using using 16 : 8 > 4> 2>1 we have T/16 > 16/16=1
When using 20, 10> 5 > 2.5> 1.25. Therefore T/16 > 20/16=1.25

Thanks Brent


That's correct.

Cheers,
Brent
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Kimberly77
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink] New post  07 Feb 2023, 14:12
Brilliant thanks BrentGMATPrepNow for confirmation.
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Re: A delivery truck starts on its route with a load of goods weighing T [#permalink]
07 Feb 2023, 14:12
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