Hi
ScottTargetTestPrep BunuelI'm slightly confused here. Your reply would be appreciated
Taking two cases here (Both starting from Saturday) with number of options to choose from and using one of them for reference,
Case 1:Saturday: 3 options, let's say
Pudding (Since Cake is not a possibility)
Sunday: 3 options,
Ice Cream Monday: 3 options,
Pie Tuesday: 3 options,
Pudding For Wednesday, let's say we got
Pie here, this should imply that for Thursday we can not have Pie and Cake (We already have cake on Friday) leaving only 2 options to choose from.
Hence, it would be 3(Sat)x3(Sun)x3(Mon)x3(Tue)x3(Wed)x2(Thur)x1(Fri) = 3^5x2
Case 2: )
Only difference here is that on Wednesday, if we have cake instead of anything else, we are left with 3 options for Thursday Saturday: 3 options, let's say
Pudding (Since Cake is not a possibility)
Sunday: 3 options,
Ice Cream Monday: 3 options,
Pie Tuesday: 3 options,
Pudding For Wednesday, let's say we got
Cake here, this means that for Thursday we can not have Cake, leaving us with 3 options to choose from
Hence, it would be 3(Sat)x3(Sun)x3(Mon)x3(Tue)x3(Wed)x3(Thur)x1(Fri) which is 3^6
Am i going wrong somewhere? Pls help!!
TIA