Forget the conventional way to solve DS questions.
We will solve this DS question using the variable approach.DS question with 2 variables : Let the original condition in a DS question contain 2 variables . In other words, there are two fewer equations than variables. Now, we know that each condition (1) and (2) would usually give us an equation, however, since we need 2 equations to match the numbers of variables and equations in the original condition, the unequal number of equations and variables should logically give us an answer C.
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Let’s apply the 3 steps suggested previously. [Watch lessons on our website to master these 3 steps]
Step 1 of the Variable Approach: Modifying and rechecking the original condition and the question.=> Let us assign variable: Shovels(s) and Rakes (r).
- Cost - Each Shovel($14) and Each Rake($9)
We have to find value of 14s + 9r.Second and the third step of Variable Approach: From the original condition, we have 2 variables (s and r).To match the number of variables with the number of equations, we need 2 equations. Since conditions (1) and (2) will provide 1 equation each, C would most likely be the answer.Let’s take a look at both conditions together .Condition(1) tells us that s : r = 2 : 3 .=> For a number 'x', ratio of s: r = 2x : 3x ----------(1)
Condition(2) tells us that s + r = 50.=> 2x + 3x = 50
=> 5x = 50 => x = 10 and hence s = 20 and r = 30.
=> Substituting the value of 's' and 'r' in 14s + 9r we will get the total cost.
Since the answer will be unique, both conditions together are sufficient by CMT 2.So, C is the correct answer.Answer: C