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A given quadratic equation ax^2 52x + 24 = 0 has 13/6 as sum of the
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10 Jan 2020, 02:14
10 Jan 2020, 02:14
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Question Stats:
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A given quadratic equation \(ax^2 – 52x + 24 = 0\) has \(\frac{13}{6}\) as sum of the roots. Find the product of the roots.
(A) \(24\)
(B) \(1\)
(C) \(12\)
(D) \(\frac{24}{5}\)
(E) \(2\)
(A) \(24\)
(B) \(1\)
(C) \(12\)
(D) \(\frac{24}{5}\)
(E) \(2\)
Joined: 20 Jul 2017
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Concentration: Entrepreneurship, Marketing
GMAT 1: 690 Q51 V30 
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Re: A given quadratic equation ax^2 52x + 24 = 0 has 13/6 as sum of the
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10 Jan 2020, 02:31
10 Jan 2020, 02:31
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For the quadratic equation, \(ax^2 + bx + c = 0\),
Sum of the roots = \(-\frac{b}{a}\) & product of the roots = \(\frac{c}{a}\)
For the given equation, \(ax^2 - 52x + 24 = 0\),
Sum of the roots = \(\frac{13}{6}\)
--> \(-\frac{(-52)}{a} = \frac{13}{6}\)
--> \(a = 52*\frac{6}{13} = 24\)
--> Product of the roots = \(\frac{c}{a} = \frac{24}{24} = 1\)
IMO Option B
Sum of the roots = \(-\frac{b}{a}\) & product of the roots = \(\frac{c}{a}\)
For the given equation, \(ax^2 - 52x + 24 = 0\),
Sum of the roots = \(\frac{13}{6}\)
--> \(-\frac{(-52)}{a} = \frac{13}{6}\)
--> \(a = 52*\frac{6}{13} = 24\)
--> Product of the roots = \(\frac{c}{a} = \frac{24}{24} = 1\)
IMO Option B
Joined: 30 Sep 2017
Posts: 943
Given Kudos: 402
GMAT 1: 720 Q49 V40
GPA: 3.8
Re: A given quadratic equation ax^2 52x + 24 = 0 has 13/6 as sum of the
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10 Jan 2020, 03:15
10 Jan 2020, 03:15
1
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Root: x1, x2
x1+x2= -(-52/a) = 13/6 --> a=24
x1.x2= 24/a = 24/24 = 1
FINAL ANSWER IS (B)
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x1+x2= -(-52/a) = 13/6 --> a=24
x1.x2= 24/a = 24/24 = 1
FINAL ANSWER IS (B)
Posted from my mobile device
