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04 Oct 2025, 11:52
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M: 486
AN: 486
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
21% (02:59) correct
79%
(03:31)
wrong
based on 195
sessions
History
Date
Time
Result
Not Attempted Yet
A global technology firm is organizing an advanced coding competition for its employees. Each multi-member team in the competition has 'a' members and every employee is on exactly one team. In each round until the fifth, multiple matches occur in parallel, with each match consisting of six teams competing against each other. From each match, only two teams advance to the next round based on their project evaluations. In the sixth round, only the final two teams compete against each other for the prize.
No team is allowed to exit the competition except through elimination. The number of teams who participated in the first round of the competition was 'm'.
From the available options, select for 'm' the number of teams who participated in the first round, and select for 'an' the number of employees who participated in the third round. Make only two selections, one in each column.
No team is allowed to exit the competition except through elimination. The number of teams who participated in the first round of the competition was 'm'.
From the available options, select for 'm' the number of teams who participated in the first round, and select for 'an' the number of employees who participated in the third round. Make only two selections, one in each column.
| M | AN | |
| 54 | ||
| 81 | ||
| 243 | ||
| 384 | ||
| 486 |
ShowHide Answer
Official Answer
M: 486
AN: 486
04 Oct 2025, 15:21
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Each round (till the 5th) has matches of 6 teams, and 2 teams advance ⇒ in every round the number of teams becomes 1/3 of what it was.
After five such rounds, the sixth round has only 2 teams.
So, if m is the number of teams in Round-1,
m/3^5 = 2 ⇒ m=2 x 3^5 = 2 x 243 = 486
Number of teams that participate in Round-3:
n=m/3^2=486/9=54
Employees in Round-3 = team size a × teams in Round-3 n = an
As n = 54, an=ax54.
Since a team is “multi-member,” a≥2 and a is an integer.
The only multiple of 54 in the list with a≥2 is 54×9=486
Therefore,
[*]m=486 teams in Round-1
[*]an=486 employees in Round-3
After five such rounds, the sixth round has only 2 teams.
So, if m is the number of teams in Round-1,
m/3^5 = 2 ⇒ m=2 x 3^5 = 2 x 243 = 486
Number of teams that participate in Round-3:
n=m/3^2=486/9=54
Employees in Round-3 = team size a × teams in Round-3 n = an
As n = 54, an=ax54.
Since a team is “multi-member,” a≥2 and a is an integer.
The only multiple of 54 in the list with a≥2 is 54×9=486
Therefore,
[*]m=486 teams in Round-1
[*]an=486 employees in Round-3
bhavyagmat
GRE 1: Q162 V161
Posts: 20
04 Oct 2025, 22:40
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Questions needs better phrasing - until 5th round , excludes 5th ( balance text in question forces you to infer it is inclusive of 5th round.
Moreover - " with each match consisting of six teams competing against each other." - so 1 match with 6 teams - or 1 match = 6 teams playing each team once in a round robin? and then 2 teams emerging..( Chatgpt says that irrespective of which option u pick here - you get the same answer)
Moreover - " with each match consisting of six teams competing against each other." - so 1 match with 6 teams - or 1 match = 6 teams playing each team once in a round robin? and then 2 teams emerging..( Chatgpt says that irrespective of which option u pick here - you get the same answer)
