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A is a set of 11 consecutive integers. Is the sum of the terms of set

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A is a set of 11 consecutive integers. Is the sum of the terms of set  [#permalink]

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New post 22 Nov 2018, 03:11
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A is a set of 11 consecutive integers. Is the sum of the terms of set A positive?

(1) The median of set A is positive
(2) The range of set A is less than the largest term in set A

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Re: A is a set of 11 consecutive integers. Is the sum of the terms of set  [#permalink]

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New post 22 Nov 2018, 04:08
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Bunuel wrote:
A is a set of 11 consecutive integers. Is the sum of the terms of set A positive?

(1) The median of set A is positive
(2) The range of set A is less than the largest term in set A


Let the Nos be X, (X+1), ............... , (X+4) , .......................... , (X+10) {11 Consequtive no.}
Sum= 11X+55

Statement(1)- Median of A Positive= (X+4)>0 => X>-4
Therefore, X= -3,-2,-1,0,1,2..................Infinity
For any value of X from above, Sum=11X+55 is positive {Try for X=-3, sum=22}
Statement(2)- Range= (X+10)-X= 10
X+10>10=> X>0
So all no. are postive, therefore sum positive.

Ans. D- Both statements are sufficient individually.
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Re: A is a set of 11 consecutive integers. Is the sum of the terms of set  [#permalink]

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New post 23 Nov 2018, 02:29
Bunuel wrote:
A is a set of 11 consecutive integers. Is the sum of the terms of set A positive?

(1) The median of set A is positive
(2) The range of set A is less than the largest term in set A



From statement 1:
For stmtn 1 to be valid all the least range of integers can be from (-5 to 5) where median would be 0, so yes the sum of Set A would be positive always
sufficient

Frm 2:
For range to be < than largest term of Set A : all terms in set need to be +ve , sufficient else in case of -ve consective integers we would end up getting range < median...

sufficient

IMO D
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Re: A is a set of 11 consecutive integers. Is the sum of the terms of set &nbs [#permalink] 23 Nov 2018, 02:29
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A is a set of 11 consecutive integers. Is the sum of the terms of set

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