Assuming sides of kite are 3,3,4,4

The diameter of the circle is 5 (hypotenuse of the right angle triangles formed by vertices of kite)

Area of kite = 2*(Area of triangle with sides 3,4,5) = 12

Area of circle = π*(2.5)^2 = approximately 19.8

Left out area = 7.8

Percentage remaining = 7.8/19.8*100 = 39%

Answer could be 39% or 40% as I haven't calculated exactly

Going with option A

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The graph is labeled below, from the inscribed angle theorem the kite must consist of two right triangles. The ratios are obviously 3:4:5 so we can assume the radius is 2.5 and the area of the triangles added up is 3*4 = 12.

The area of the circle is \((\frac{5}{2})^2 * \pi \approx \frac{25}{4} * \pi \). Then the ratio that is cut out is: \(12/(\frac{25}{4} * \pi) = \frac{4*12}{25\pi} \approx \frac{4*12}{25*3*1.05} = \frac{16}{25}/1.05 = 64\%/1.05 \approx 64\% - 5\%*64\% = 64\% - 3.2\% = 60.8\%\). Then there is roughly 39.2% not cut out.
(The answers were quite close which normally isn't the case, so don't bother too much about the estimations. Most of the time 3.14 ->3 is a sufficient approximation).

Ans: A

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