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A machine puts c caps on bottles in m minutes. How many hours will it

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A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 16 May 2016, 02:45
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A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c
B. bm/(60c)
C. bc/(60m)
D. 60b/(cm)
E. b/(60cm)
[Reveal] Spoiler: OA

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 16 May 2016, 03:05
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A machine puts c caps on bottles in m minutes.
So, the machine puts 1 cap in m/c minutes

To put caps on b bottles, the machine will take bm/c minutes
In order to calculate the no. of hours taken , divide the product by 60.
So, our answer is bm/60c

Answer : B

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 16 May 2016, 05:27
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The key for me is to realise that 1 bottle can only have 1 cap.
(ie bottles can be multiplied with minutes/cap and cancel out leaving only time)

Without that it seems super difficult but actually is a very straightforward calculation.

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 17 May 2016, 05:23
We can plug in simple numbers

2 caps per 1 min,, then rate= 2 caper/min

Put b= 120 or 60 bottles.. I used 120 bottles

120= 2 * t.....>t=60 min =1 hr

Scanning the answer choice.. Eliminate A & D as you need to divide minute by 60.
Eliminate E as CM should be together.

Substitute number in choice B & C

In bm/60c= (120*1)/ (2 *60) = 1

Answer: B

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 24 Apr 2017, 15:07
Bunuel wrote:
A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c
B. bm/60c
C. bc/60m
D. 60b/cm
E. b/60cm


A machine puts c caps on bottles in M minutes. A bottle can only have 1 cap, so this means that in M minutes, the machine will cap C bottles

\(\frac{M minutes}{C bottles}\)

How many hours will it take to put caps on B bottles? This is a comparison ratio:

\(\frac{M minute}{C bottles}\) * \(\frac{1 hour}{60 minutes}\) = \(\frac{X hours}{B bottles}\)

This becomes:

\(\frac{(M minute)(B bottles)(1 hour)}{(C bottles)(60 minutes)}\) = \(x hours\)

Simplify to:

\(\frac{mb}{60c}\) = \(x hours\)

This question's only difficulty is seeing that they want you to do a comparison between c bottles and b bottles. They intentionally made the letters confusing for those that could only see b should stand for bottles.

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 20 Sep 2017, 10:37
W2*T1=W1*T2

Always works. Just switch the work and Keep all other factors on the same side.

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Re: A machine puts c caps on bottles in m minutes. How many hours will it [#permalink]

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New post 09 Nov 2017, 13:39
c caps in m minutes.
Hence, in 1 hour, the machine puts \(\frac{60c}{m}\) caps. This is the rate.
Work is given as b.

\(W=b ; R=\frac{60c}{m} ; T=?\)

\(T= \frac{W}{R} = \frac{b*m}{60c}\)
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Re: A machine puts c caps on bottles in m minutes. How many hours will it   [#permalink] 09 Nov 2017, 13:39
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