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A man purchased some pens, pencils and erasers. Can the number of eras

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A man purchased some pens, pencils and erasers. Can the number of eras [#permalink]

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A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?

(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers.
(2) Total number of items purchased was 21.
[Reveal] Spoiler: OA

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A man purchased some pens, pencils and erasers. Can the number of eras [#permalink]

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New post 04 Jul 2017, 23:46
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Bunuel wrote:
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?

(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers.
(2) Total number of items purchased was 21.


(1) gives us

Pen : Pencil : Eraser
if the ratio is

3:3:3 then we can say Yes

but if the ratio is
1:3:9 then its No
Not sufficient

(2) Total is 21

Now
Pen : Pencil : Eraser
x:y:z
x+y+z = 21
Not sufficient

On combining
x/y=y/z
y^2 = xz

Lets take one example
y = 6 and x = 12 and y = 3
Pen : Pencil : Eraser
12:6:3 answer would be Yes

"Can the number of erasers purchased be 3" Yes possible

Hence C
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Last edited by Luckisnoexcuse on 27 Sep 2017, 20:21, edited 1 time in total.

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A man purchased some pens, pencils and erasers. Can the number of eras [#permalink]

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New post 27 Sep 2017, 20:02
Bunuel wrote:
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?

(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers.
(2) Total number of items purchased was 21.


Answer C



Solution:



Let the number of pen be X,
the number of pencil be Y,
the number of Erasers be Z.

Statement 1 - \frac{X}{Y} = \frac{Y}{Z}
=> XZ = \(Y^2\) -------------------------------------------------Equation I

Y can be any number.

Statement 1 Not sufficient




Statement 2 - X + Y + Z = 21 -------------------------------------------------Equation II

Y can be any number.

Statement 2 Not sufficient




Together 1 & 2:

From equation 1
\(Y^2\) = Can only be equal to 4,9,16, and 25.
so, Y can be 2, 3, 4, 5.

Only when X = 16, Z = 1 and Y = 4 will satisfy both of the above equations.

hence Y = 4 and not 3 so

Together both the statements are sufficient. C

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Re: A man purchased some pens, pencils and erasers. Can the number of eras [#permalink]

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New post 17 Oct 2017, 04:17
Can someone please give another simple technique to solve this?

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Re: A man purchased some pens, pencils and erasers. Can the number of eras [#permalink]

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New post 28 Oct 2017, 03:08
atomicmass wrote:
Bunuel wrote:
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?

(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers.
(2) Total number of items purchased was 21.


Answer C



Solution:



Let the number of pen be X,
the number of pencil be Y,
the number of Erasers be Z.

Statement 1 - \frac{X}{Y} = \frac{Y}{Z}
=> XZ = \(Y^2\) -------------------------------------------------Equation I

Y can be any number.

Statement 1 Not sufficient




Statement 2 - X + Y + Z = 21 -------------------------------------------------Equation II

Y can be any number.

Statement 2 Not sufficient




Together 1 & 2:

From equation 1
\(Y^2\) = Can only be equal to 4,9,16, and 25.
so, Y can be 2, 3, 4, 5.

Only when X = 16, Z = 1 and Y = 4 will satisfy both of the above equations.

hence Y = 4 and not 3 so

Together both the statements are sufficient. C



consider,
there are 6 pencils, 12 pens and 3 erasures.
then also pencil^2= pens*erasures holds.
6^2=36
12*3=36.
Answer would still remain C. Because we are asked to find "can the numbers of erasures purchased be 3?" So, yes in one scenario it can be.

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Re: A man purchased some pens, pencils and erasers. Can the number of eras [#permalink]

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New post 28 Oct 2017, 04:07
Bunuel wrote:
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?

(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers.
(2) Total number of items purchased was 21.


Hi Bunuel, may be you require to look into the Q ...

the wordings are CAN the erasers be 3...

(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers.
let the ratio be 1:1:1...all three can be 3 each 3:3:3... YES erasers CAN be 3
also each can be 4:4:4 that is 4 each... ans is No

BUt we are looking for CAN, so ans is YES and should be sufficient

(2) Total number of items purchased was 21
x+y+z=21... we can easily find the match where erasers are 3 and remaining two add up to 18
so again should be suffficient..

But if the Q was "IS number of erasers purchased 3", each statement would be insuff
two solution that will fit in..
1) 12:6:3.....12+6+3=21....Also ratio is 12:6 or 2:1 and 6:3 or 2;1.... 6^2=12*3... so eraser can be 3
2) 16:4:1...16+4+1=21...Also ratio is 16:4=4:1 and 4:1....4^2=16*1...... so eraser will not be 3

and answer should be E for "is number of erasers 3?"..
and ans should be D for " can the number of erasers be 3?"
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Re: A man purchased some pens, pencils and erasers. Can the number of eras   [#permalink] 28 Oct 2017, 04:07
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