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Let distance be d

S1
Travelled d/4 at 15m/h
Time = d/4/15 = d/60

Travelled 3d/4 at 20m/h
Time = 3d/4/20 = 3d/20

We don't know anything about time taken, so cannot calculate d
Insufficient

S2
The time for which he travelled at 20 miles per hour was 5 hours greater than the time for which he travelled at 15 miles per hour.
We don't know the distances for which the speed was 20m/h and 15m/h
Insufficient

Combined,
3d/20 - d/60 =5
d=240
Sufficient
Answer C
Bunuel
A man travelled from one city to another. What is the distance between the two cities?

(1) He travelled the first 1/4 of his distance at a uniform speed of 15 miles per hour. Thereafter, he increased his speed to 20 miles per hour.
(2) The time for which he travelled at 20 miles per hour was 5 hours greater than the time for which he travelled at 15 miles per hour.


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