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SajjadAhmad
A manager is forming a 6-person team to work on a certain project. From the 11 candidates available for the team, the manager has already chosen 3 to be on the team. In selecting the other 3 team members, how many different combinations of 3 of the remaining candidates does the manager have to choose from?

A. 6

B. 24

C. 56

D. 120

E. 462

241/826

The number of ways to select the 3 remaining team members from 8 remaining available candidates is 8C3 = (8 x 7 x 6)/(3 x 2) = 8 x 7 = 56.

Answer: C
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Since the manager already chose 3 of the 6 team members, he has to chose the remaining 3 from 8 (11 - 3 =8) options ==> 8C3 = 56 ==> C is the answer
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