Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 23 May 2017, 20:16

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

A merchant paid $300 for a shipment of x identical calculato  post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message Senior Manager Joined: 30 May 2005 Posts: 276 Followers: 1 Kudos [?]: 40 [0], given: 0 A merchant paid$300 for a shipment of x identical calculato [#permalink]

Show Tags

03 Jun 2005, 01:55
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A merchant paid $300 for a shipment of x identical calculators. The merchant used 2 of the calculators as demonstrators and sold each of the others for$5 more than the average (arithmetic mean) cost of the x calculators. If the total revenue from the sale of the calculators was $120 more than the cost of the shipment, how many calculators were in the shipment? (A) 24 (B) 25 (C) 26 (D) 28 (E) 30 Senior Manager Joined: 17 May 2005 Posts: 272 Location: Auckland, New Zealand Followers: 1 Kudos [?]: 13 [0], given: 0 Show Tags 03 Jun 2005, 02:31 The total amount paid was$300 for x calculators.
The amount paid for each calculator = 300/x

The amount each calculator was sold for = 300/x + 5 = (300+5x)/x

The number of calculators sold = (x-2)

Revenue earned = 300 + 120 = 420

Revenue earned = number of calculators sold * selling price of each calculator.

Therefore:
[(300+5x)/x]*(x-2) = 420
[(300+5x)(x-2)]/x=420
(300+5x)(x-2)=420x
300x+5x^2-600-10x=420x
5x^2-130x-600=0
5(x^2-26x-120)=0
x^2 - 26x - 120 = 0
(x - 30) (x - 4) = 0

x = 30 or -4

as it can't be -4, answer has to be 30.
03 Jun 2005, 02:31
Display posts from previous: Sort by