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cfc198
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Assume the total quantity as 100 litre {try this for all similar problems}.
Now for given 20% water in mixture means, 20 L water and 80 L Milk.

Also assume the cost as 1$/litre so CP = 80$ and SP = 100+10%(100) => 110$

NOTE : Marked Price is the price tag on the items. It may or it may not {in case of discounts} be equal to SP.

So profit of 30$ on 80$ which gives 37.5 % profit [(30/80)*100]
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cfc198
A milk-man sells milk after mixing water to it to such a extent that water accounts for 20% of the mixture. If he sells at a mark-up rate of 10%, find his actual profit percentage.

1. 30%
2. 32%
3. 33.33%
4. 37.5%
5. 40%

Lets take price of the mixture is 100, which has price of milk as 80 and of water as 20.

Mark up price is 110% of 100 is 110.

Actual price of milk is 80 and selling price is 110, so profit percent is 30/80*100% = 37.5%.

D is correct.
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