To solve this, we need to calculate the number of gallons shipped based on each combination of 15-gallon and 25-gallon drums. The total number of gallons shipped should equal 500,000, and the number of drums of each type should be between 10,000 and 15,000. Let’s go step by step:
Step 1: Formulate the equationLet x be the number of 15-gallon drums and y be the number of 25-gallon drums. Then:
15x + 25y = 500,000
Step 2: Simplify the equationDivide through by 5:
3x + 5y = 100,000
Step 3: Solve for valid combinationsWe now test the given values of x(number of 15-gallon drums) to find y(number of 25-gallon drums) and ensure both x and y fall within the limits of 10,000 to 15,000 drums.
1. If x = 10,000:
3(10,000) + 5y = 100,000 \(\implies\) 30,000 + 5y = 100,000 \(\implies\) 5y = 70,000 \(\implies\) y = 14,000
y = 14,000 \) is valid.
2. If x = 11,000:
3(11,000) + 5y = 100,000 \(\implies\) 33,000 + 5y = 100,000 \(\implies\) 5y = 67,000 \(\implies\) y = 13,400
y = 13,400 is valid.
3. If x = 12,000:
3(12,000) + 5y = 100,000 \(\implies\) 36,000 + 5y = 100,000 \(\implies\) 5y = 64,000 \(\implies\) y = 12,800
y = 12,800 is valid.
4. If x = 13,000:
3(13,000) + 5y = 100,000 \(\implies\) 39,000 + 5y = 100,000 \(\implies\) 5y = 61,000 \(\implies\) y = 12,200
y = 12,200 is valid.
5. If x = 15,000:
3(15,000) + 5y = 100,000 \(\implies\) 45,000 + 5y = 100,000 \(\implies\) 5y = 55,000 \(\implies\) y = 11,000
y = 11,000 is valid.
6. If x = 17,000:
3(17,000) + 5y = 100,000 \(\implies\) 51,000 + 5y = 100,000 \(\implies\) 5y = 49,000 \(\implies\) y = 9,800
y = 9,800 is not valid because y < 10,000.
Step 4: List valid combinationsThe valid combinations are:
x = 10,000, y = 14,000
x = 11,000, y = 13,400
x = 12,000, y = 12,800
x = 13,000, y = 12,200
x = 15,000, y = 11,000
Final Answer:One valid combination is
15,000 (15-gallon drums) and
11,000 (25-gallon drums). It satisfies both:
- 15(15,000) + 25(11,000) = 500,000
- The range for x (15-gallon drums) and y (25-gallon drums) is within 10,000–15,000