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a -> number of 15-gallon drums
b -> number of 25-gallon drums

15a + 25b = 500k
=> 3a + 5b = 100k

10k <= a and b <= 15k

We need to find a and b from the options.

(1) Reject 17k for both (because neither a nor b can be >15k).
(2) Try 10k

a) if a = 10k, then 5b = 70k => b = 14k. Not available in the options. Reject.
b) if b = 10k, then 3a = 50k => no integer number of drums is possible here. Reject.

(3) Try 11k

a) If a = 11k, then 5b = 67k. The value of b we get here is not an available option. Reject.
b) If b = 11k, then 3a = 45k => a = 15k. We got our answer.

Answer: (15000,11000)

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Nice! You have provided a detailed approach.
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To solve this, we need to calculate the number of gallons shipped based on each combination of 15-gallon and 25-gallon drums. The total number of gallons shipped should equal 500,000, and the number of drums of each type should be between 10,000 and 15,000. Let’s go step by step:

Step 1: Formulate the equation
Let x be the number of 15-gallon drums and y be the number of 25-gallon drums. Then:

15x + 25y = 500,000

Step 2: Simplify the equation
Divide through by 5:

3x + 5y = 100,000

Step 3: Solve for valid combinations
We now test the given values of x(number of 15-gallon drums) to find y(number of 25-gallon drums) and ensure both x and y fall within the limits of 10,000 to 15,000 drums.

1. If x = 10,000:
3(10,000) + 5y = 100,000 \(\implies\) 30,000 + 5y = 100,000 \(\implies\) 5y = 70,000 \(\implies\) y = 14,000
y = 14,000 \) is valid.

2. If x = 11,000:
3(11,000) + 5y = 100,000 \(\implies\) 33,000 + 5y = 100,000 \(\implies\) 5y = 67,000 \(\implies\) y = 13,400
y = 13,400 is valid.

3. If x = 12,000:
3(12,000) + 5y = 100,000 \(\implies\) 36,000 + 5y = 100,000 \(\implies\) 5y = 64,000 \(\implies\) y = 12,800
y = 12,800 is valid.

4. If x = 13,000:
3(13,000) + 5y = 100,000 \(\implies\) 39,000 + 5y = 100,000 \(\implies\) 5y = 61,000 \(\implies\) y = 12,200
y = 12,200 is valid.

5. If x = 15,000:
3(15,000) + 5y = 100,000 \(\implies\) 45,000 + 5y = 100,000 \(\implies\) 5y = 55,000 \(\implies\) y = 11,000
y = 11,000 is valid.

6. If x = 17,000:
3(17,000) + 5y = 100,000 \(\implies\) 51,000 + 5y = 100,000 \(\implies\) 5y = 49,000 \(\implies\) y = 9,800
y = 9,800 is not valid because y < 10,000.

Step 4: List valid combinations
The valid combinations are:
x = 10,000, y = 14,000
x = 11,000, y = 13,400
x = 12,000, y = 12,800
x = 13,000, y = 12,200
x = 15,000, y = 11,000

Final Answer:
One valid combination is 15,000 (15-gallon drums) and 11,000 (25-gallon drums). It satisfies both:
  1. 15(15,000) + 25(11,000) = 500,000
  2. The range for x (15-gallon drums) and y (25-gallon drums) is within 10,000–15,000
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Thank you so much poojaarora1818 didi
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Nice! You have provided a detailed approach.
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1. The question asks us to find a possible combination of 15 and 25 gallon drums that would give a total of 500000, while adhering to the rules.

2. Let the number of 15 and 25 gallon drums be a and b, respectively. Then, we need to find a combination (a,b) so that \(15a + 25b = 500000\) for \(10000 \leq a,b \leq 15000\).

3. \(15a + 25b = 500000 \rightarrow 3a + 5b = 100000 \rightarrow b = \frac{100000 - 3a}{5}\). Now let's test a and see if b works:

- a = 10000. \(b = \frac{100000 - 3a}{5} = \frac{100000 - 3 * 10000}{5} = 14000\), which doesn't work.
- a = 11000. \(b = \frac{100000 - 3a}{5} = \frac{100000 - 3 * 11000}{5} = 13400\), which doesn't work.
- a = 12000. \(b = \frac{100000 - 3a}{5} = \frac{100000 - 3 * 12000}{5} = 12800\), which doesn't work.
- a = 13000. \(b = \frac{100000 - 3a}{5} = \frac{100000 - 3 * 13000}{5} = 12200\), which doesn't work.
- a = 15000. \(b = \frac{100000 - 3a}{5} = \frac{100000 - 3 * 15000}{5} = 11000\), which works.
- a = 17000. \(b = \frac{100000 - 3a}{5} = \frac{100000 - 3 * 17000}{5} = 9800\), which doesn't work.

4. Our answer will be: Number of 15-gallon drums - 15000 and Number of 25-gallon drums - 11000.
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