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# A person purchased a total of 2t + 1 tickets. Some cost \$4

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Eternal Intern
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A person purchased a total of 2t + 1 tickets. Some cost \$4 [#permalink]

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06 Aug 2003, 09:45
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A person purchased a total of 2t + 1 tickets. Some cost \$4 the remaining cost \$7. If 3 more \$ 4 than \$7 tickets were purchased. what equation can express, the total cost in dollars of the 2t + 1 tickets?

Victor
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06 Aug 2003, 10:07
total# of tickets = 2t+1

let, x = # of \$7 tickets
so, x+3 = # of \$4 tickets

So, total # of tickets in terms of x = 2x+3

so, 2x+3 = 2t+1
=> x = t-1 ---> # of \$7 tickets

so, x+3 = t+2 ---> # of \$4 tickets

So, total \$ amount = 7(t-1) + 4(t+2) = 11t+1 dollars

Last edited by prakuda2000 on 06 Aug 2003, 13:29, edited 1 time in total.

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Eternal Intern
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06 Aug 2003, 12:57
3 more \$ 4 than \$7 tickets were purchased.

Looks like you got that wrong, Prakunda,
I still think it can only be solved with picking numbers.

Victor
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06 Aug 2003, 13:30
Yes, I corrected the \$4, \$7 ticket. See changed solution

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06 Aug 2003, 13:30
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