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Given:
...................Time..Speed..Distance
Slower Plane..3h.....x.... ...........
Faster plane.. .. x+60 ... ...........
(Time*Speed=Distance)

.......................Time.....Speed...Dis
Slower Plane...3h ......x .... 3x...
Faster plane..(3x/x+60)...(x+60)...3x....

To find: Faster plan time

(1) The trip was 1,590 miles
3x= 1590 miles
x= 530 miles
With the value of x we can easily find the time of faster train
Sufficient

(2) The slower plane travels at 530 miles per hour.
x= 530 miles.
Sufficient

Answer: D
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Faster Plane Speed: S
Then Slower Plane Speed: S-60
Slower Plane Traveled for Three Hours, Hence the total distance covered in 3 Hours would be: 3(S-60)

1. The Trip was 1590 miles long, hence the slow plane covered 1590 miles; 1590 = 3(S-60);
S=590; Then time taken by faster plane would be: 1590/590; Sufficient.

2. Slower plane speed was 530; 530 = S-60; This provides S = 590; and the slower plane travelled for three hours, the total distance covered would be 530*3 = 1590; Then faster plane would take 1590/590; Sufficient.
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