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10 Mar 2025, 00:30
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
86% (01:19) correct
14%
(02:06)
wrong
based on 63
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A plane averages 60 miles per hour slower than a second plane. If the slower plane completes a particular trip in three hours, how long will the faster plane take to complete the same trip?
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
10 Mar 2025, 02:08
Kudos
Bookmarks
Bunuel
First plane speed = S | Time = 3 hours
Second plane speed = S+60 | T = ?
Distance is constant so
S*3 = (S+60)*T
i.e. to calculate T we need the value of S
Question: S = ?
Statement 1: D = 1590
i.e. 1590 = S*3
i.e. S = 530
SUFFICIENT
Statement 2: S = 530
SUFFICIENT
Answer: Option D
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10 Mar 2025, 03:10
Kudos
Bookmarks
Step 1: Define variables
Let S be the speed of the slower plane.
Let F be the speed of the faster plane.
Given that the slower plane is 60 mph slower than the faster plane:
F = S + 60
Step 2: Use the given information
The slower plane takes 3 hours for the trip, so the total distance (D) is:
D = S × 3
Step 3: Analyze the statements
(1) The trip was 1,590 miles.
- Using D = 1,590, we get:
S × 3 = 1,590
S = 1,590 / 3 = 530 mph
- This allows us to determine S, so we can also find F:
F = 530 + 60 = 590 mph
- Now, time for the faster plane:
Time = Distance / Speed = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
(2) The slower plane travels at 530 miles per hour.
- This directly gives S = 530 mph, so we can compute F:
F = 530 + 60 = 590 mph
- Since distance is S × 3 = 1,590, we already know the distance.
Time for the faster plane:
Time = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
Step 4: Conclusion
Each statement alone is sufficient to answer the question.
Answer: D (Each statement alone is sufficient)
Let S be the speed of the slower plane.
Let F be the speed of the faster plane.
Given that the slower plane is 60 mph slower than the faster plane:
F = S + 60
Step 2: Use the given information
The slower plane takes 3 hours for the trip, so the total distance (D) is:
D = S × 3
Step 3: Analyze the statements
(1) The trip was 1,590 miles.
- Using D = 1,590, we get:
S × 3 = 1,590
S = 1,590 / 3 = 530 mph
- This allows us to determine S, so we can also find F:
F = 530 + 60 = 590 mph
- Now, time for the faster plane:
Time = Distance / Speed = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
(2) The slower plane travels at 530 miles per hour.
- This directly gives S = 530 mph, so we can compute F:
F = 530 + 60 = 590 mph
- Since distance is S × 3 = 1,590, we already know the distance.
Time for the faster plane:
Time = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
Step 4: Conclusion
Each statement alone is sufficient to answer the question.
Answer: D (Each statement alone is sufficient)
