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Difficulty:
25%
(medium)
Question Stats:
86% (02:47) correct
14%
(03:14)
wrong
based on 2117
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A portion of an automobile test track is divided into Segment A, Segment B, and Segment C, in that order. In a performance test on a car, the car traveled Segment A at a constant speed of 140 kilometers per hour (km/h). Immediately after this, the car rapidly slowed on Segment B and then traveled on Segment C at a constant speed of 70 km/h. The length of Segment C is 3 times the length of Segment A, and it took a total of 42 minutes for the car to travel both segments A and C.
In the table, select the length of Segment A, in kilometers, and select the length of Segment C, in kilometers. Make only two selections, one in each column.
In the table, select the length of Segment A, in kilometers, and select the length of Segment C, in kilometers. Make only two selections, one in each column.
ID: 100359
|
Length of Segment A (kilometers) |
Length of Segment C (kilometers) |
|
| 8 | ||
| 14 | ||
| 24 | ||
| 42 | ||
| 72 | ||
| 126 |
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Let length of segment A=x
So length of segment C=3x
And total time taken is 42 min =42/60 hours= 0.7 hours
So we will use Total time= distance in A/Speed in A + distance in C/Speed in C
0.7= x/140 + 3x/70
0.7*140= x+6x
.7*140=7x
x=14
So length of segment A=14
Length of segment C=42
Posted from my mobile device
So length of segment C=3x
And total time taken is 42 min =42/60 hours= 0.7 hours
So we will use Total time= distance in A/Speed in A + distance in C/Speed in C
0.7= x/140 + 3x/70
0.7*140= x+6x
.7*140=7x
x=14
So length of segment A=14
Length of segment C=42
Posted from my mobile device
Posts: 16,403
Official Explanation
We are asked to determine the lengths of two segments of an automobile test track. The passage states that a car traveled Segment A at a constant rate of 140 km/h and traveled Segment C at a constant rate of 70 km/h, which indicates that it took the car twice as much time to cover a given unit of distance in Segment C as it took to cover the same distance in Segment A. The passage further states that the length of Segment C is 3 times the length of Segment A. Because the car took twice the time to cover a given distance in Segment C as in Segment A, and because Segment C was 3 times as long as Segment A, it can be further determined that the car spent 6 times as much time traveling Segment C as it did traveling Segment A. The passage indicates that it took a total of 42 minutes for the car to travel both segments A and C, and 42 minutes is equal to 0.7 h (42/60). Therefore, given that the car spent 6 times as much of the total combined time on Segment C as it did on Segment A, it can be calculated that the car spent 0.1 h on Segment A and 0.6 h on Segment C. Because we know that the car was traveling at 140 km/h for 0.1 h on Segment A, we can determine that Segment A was 14 kilometers long.
The correct answer is 14.
As noted in the analysis above, the car spent 0.6 h traveling Segment C. Because we know that the car was traveling at 70 km/h for 0.6 h on Segment C, we can determine that Segment C was 42 kilometers long.
The correct answer is 42.
We are asked to determine the lengths of two segments of an automobile test track. The passage states that a car traveled Segment A at a constant rate of 140 km/h and traveled Segment C at a constant rate of 70 km/h, which indicates that it took the car twice as much time to cover a given unit of distance in Segment C as it took to cover the same distance in Segment A. The passage further states that the length of Segment C is 3 times the length of Segment A. Because the car took twice the time to cover a given distance in Segment C as in Segment A, and because Segment C was 3 times as long as Segment A, it can be further determined that the car spent 6 times as much time traveling Segment C as it did traveling Segment A. The passage indicates that it took a total of 42 minutes for the car to travel both segments A and C, and 42 minutes is equal to 0.7 h (42/60). Therefore, given that the car spent 6 times as much of the total combined time on Segment C as it did on Segment A, it can be calculated that the car spent 0.1 h on Segment A and 0.6 h on Segment C. Because we know that the car was traveling at 140 km/h for 0.1 h on Segment A, we can determine that Segment A was 14 kilometers long.
The correct answer is 14.
As noted in the analysis above, the car spent 0.6 h traveling Segment C. Because we know that the car was traveling at 70 km/h for 0.6 h on Segment C, we can determine that Segment C was 42 kilometers long.
The correct answer is 42.
General Discussion
bM22
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Speed in Segment A = 140km,
Speed in Segment B = unknown
Speed in Segment C = 70km.
Length of segment A = x,
Length of segment C = 3x.
total time taken to cover Segment A & B = 42/60 = 0.7 hrs.
The equation which will be formed is: x/140 + 3x/70 = 7x/140 = 7/10.
=> x = 14 km, 3x = 42 km
Answer : Segment A: 14 km, Segment B = 42 km.
Speed in Segment B = unknown
Speed in Segment C = 70km.
Length of segment A = x,
Length of segment C = 3x.
total time taken to cover Segment A & B = 42/60 = 0.7 hrs.
The equation which will be formed is: x/140 + 3x/70 = 7x/140 = 7/10.
=> x = 14 km, 3x = 42 km
Answer : Segment A: 14 km, Segment B = 42 km.
parkhydel
Let us employ weighted average.
3 segments
Distance Rate Time
A ......... 140 km/h
B
C......... 70 km/h
Length of C = 3A
Total Time for to pass A + C or 4A = 42 min = 42/60 = (7/10)h
Ratio of Segment A rate to C rate is \(\frac{140}{70 }\) =\(\frac{2}{1 }\)
Ratio of Distance of Segment A to C =3A is \(\frac{1}{3 }\)
So, time = Distance/Ration
For segment A: 1/2
For segment C 3/1
Total 3.5 or 7/2
The proportion for segment A becomes \(\frac{0.5}{3.5}\) = \(\frac{1}{7}\) * \(\frac{7}{10 }\)h = \(\frac{1}{10}\)h Thus, 140km/h * 1/10 = 14km
The proportion for segment A becomes \(\frac{3}{3.5}\) = \(\frac{6}{7}\)* \(\frac{7}{10 }\)h = \(\frac{6}{10}\)h Thus, 70km/h * 6/10 =42km
Can be solved using the options directly
only pairs possible with the condition of x and 3x requirements
8,24
14,42
24,72
Test cases, 1st case calculated brings the time to about 33mins (given is 42 so eliminate)
2nd case is 6mins and 36mins for Segment A and Segment C respectively.
So 14 and 42 are the correct options.
only pairs possible with the condition of x and 3x requirements
8,24
14,42
24,72
Test cases, 1st case calculated brings the time to about 33mins (given is 42 so eliminate)
2nd case is 6mins and 36mins for Segment A and Segment C respectively.
So 14 and 42 are the correct options.
Distance Speed Time
Segment A: a 140 km/h
Segment B:
Segment C: 3a 70 km/h
\(42 min = \frac{42}{60} h = \frac{7}{10} h\)
\(\frac{a}{140} + \frac{3a}{70} = \frac{a}{140} + \frac{6a}{140} = \frac{7a}{140} = \frac{a}{20} = \frac{7}{10}\)
=> a = 14
=> 3a = 42
Segment A: 14
Segement C: 42
Segment A: a 140 km/h
Segment B:
Segment C: 3a 70 km/h
\(42 min = \frac{42}{60} h = \frac{7}{10} h\)
\(\frac{a}{140} + \frac{3a}{70} = \frac{a}{140} + \frac{6a}{140} = \frac{7a}{140} = \frac{a}{20} = \frac{7}{10}\)
=> a = 14
=> 3a = 42
Segment A: 14
Segement C: 42
parkhydel
Responding to a pm: How to do it using ratios?
Speeds A : C = 2:1
Distance A : C = 1 : 3
Hence ratio of time taken A : C = 1/2 : 3 = 1 : 6
Of the total 42 mins then, 6 mins were spent on A and 36 mins on C.
Distance of A = 140 * 6/60 = 14 km
Distance of C = 70 * 36/60 = 42 km
Select 14 and 42
Here is a discussion on Ratios: https://anaprep.com/arithmetic-ratios-t ... ll-starts/
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could you perhaps show youre calculations ? thank you
whatsarc
GMAT Focus 1: 615 Q83 V81 DI78 
Posts: 409
I think basically the calculation here revolves around Distance, rate, and time.
Ex : for 14 and 42 case :
rate * time = Distance
140km/hr * time = 14 km
time = 0.1 hr
0.1 hr * 60 min / 1 hr =6 mins
and similarly,
70km/hr * time = 42 km
time = 0.6 hr
0.6 hr * 60 min/ 1 hr = 36 mins
so, 6 + 36 = 42 mins
I hope this helps
Ex : for 14 and 42 case :
rate * time = Distance
140km/hr * time = 14 km
time = 0.1 hr
0.1 hr * 60 min / 1 hr =6 mins
and similarly,
70km/hr * time = 42 km
time = 0.6 hr
0.6 hr * 60 min/ 1 hr = 36 mins
so, 6 + 36 = 42 mins
I hope this helps
LoneCase
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