|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
05 Feb 2022, 04:26
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (01:50) correct
26%
(02:28)
wrong
based on 505
sessions
History
Date
Time
Result
Not Attempted Yet
A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey and the predator covers as much distance in 2 leaps as 3 leaps of the prey. What is the ratio of the speed of the predator to that of the prey ?
(A) 11 : 9
(B) 10 : 9
(C) 1 : 1
(D) 9 : 10
(E) 9 : 11
(A) 11 : 9
(B) 10 : 9
(C) 1 : 1
(D) 9 : 10
(E) 9 : 11
Attachment:
Prey.png
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
04 Mar 2024, 09:41
Kudos
Bookmarks
Official Solution:
A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey, and the predator covers as much distance in 2 leaps as 3 leaps of the prey. What is the ratio of the speed of the predator to that of the prey?
A. 11 : 9
B. 10 : 9
C. 1 : 1
D. 9 : 10
E. 9 : 11
Assuming one leap of the predator is \(x\) units and one leap of the prey is \(y\) units, then:
In 4 leaps, the predator covers the distance of \(4x\) units.
In 6 leaps, the prey covers the distance of \(6y\) units.
Note that these distances take the predator and the prey the same amount of time.
Since it is also given that the predator covers as much distance in 2 leaps as the prey does in 3 leaps, we get \(2x = 3y\). Substituting \(2x = 3y\) in the above, we get \(6y = 2(3y) = 4x\).
Thus, in the same time period, both the predator and the prey cover the same distance of \(4x\) units, indicating an equal speed.
Answer: C
A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey, and the predator covers as much distance in 2 leaps as 3 leaps of the prey. What is the ratio of the speed of the predator to that of the prey?
A. 11 : 9
B. 10 : 9
C. 1 : 1
D. 9 : 10
E. 9 : 11
Assuming one leap of the predator is \(x\) units and one leap of the prey is \(y\) units, then:
In 4 leaps, the predator covers the distance of \(4x\) units.
In 6 leaps, the prey covers the distance of \(6y\) units.
Note that these distances take the predator and the prey the same amount of time.
Since it is also given that the predator covers as much distance in 2 leaps as the prey does in 3 leaps, we get \(2x = 3y\). Substituting \(2x = 3y\) in the above, we get \(6y = 2(3y) = 4x\).
Thus, in the same time period, both the predator and the prey cover the same distance of \(4x\) units, indicating an equal speed.
Answer: C
General Discussion
kungfury42
Joined: 07 Jan 2022
Last visit: 31 May 2023
Posts: 580
Given Kudos: 724
Schools: NUS '25 (A)
GMAT 1: 740 Q51 V38
GPA: 4
Products:
05 Feb 2022, 13:48
Kudos
Bookmarks
Let the prey cover a distance of D in each leap. Total distance it covers in 3 leaps = 3D which is equal to the total distance the predator covers in 2 leaps which means the total distance predator covers in each leap = 3D/2 = 1.5D
Now distance covered by prey in 6 leaps = 6D
Distance covered by predator in 4 leaps = 4*1.5D = 6D
And we've been given that both of them take the same time to do so (making 6 leaps and 4 leaps respectively)
If time is constant, Distance is directly proportional to speed and since distance is the same too (in this case), their speeds will also be equal.
Therefore, ratio of their speeds = 1:1, hence, option C.
Posted from my mobile device
Now distance covered by prey in 6 leaps = 6D
Distance covered by predator in 4 leaps = 4*1.5D = 6D
And we've been given that both of them take the same time to do so (making 6 leaps and 4 leaps respectively)
If time is constant, Distance is directly proportional to speed and since distance is the same too (in this case), their speeds will also be equal.
Therefore, ratio of their speeds = 1:1, hence, option C.
Posted from my mobile device
