Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 0911:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 10
11:00 AM IST
-01:00 PM IST
Attend this session to evaluate your current skill level, learn process skills, and solve through tough Arithmetic questions 
Nov 1305:30 AM PST
-06:00 PM PST
We are excited to bring you the Fall edition of the MBA Spotlight Fair! Meet admission officers from the top 20 MBA programs—including HBS, Stanford, and Wharton—as you prepare for Round 2 applications.
19 Jan 2022, 07:15
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
63% (02:57) correct
37%
(02:55)
wrong
based on 86
sessions
History
Date
Time
Result
Not Attempted Yet
A recent survey examined the working arrangements of households of married couples with no children. It was found that 82% of the households had at least one working member. In 30% of the household with the women not working, the man also does not work. In 60% of the households in which the man doesn't work, the woman also does not work. What is the probability that both the man and the woman work?
A. 13%
B. 22%
C. 28%
D. 32%
E. 34%
A. 13%
B. 22%
C. 28%
D. 32%
E. 34%
19 Jan 2022, 23:30
Kudos
Bookmarks
Let the total number of households be 100, the number of households in which women don't work be 'x' and the number of households in which the men don't work be 'y'. Also, let the number of households where only women work be 'w', where only men work be 'm' and where both women and men work be 'mw'.
(1) The number of households where neither the man nor the woman work is 100 - 82 = 18.
(2) "In 30% of the households with the woman not working the man also doesn't work". So:
3x/10=18...> x=60. T/4, the number of households in which women work is 40.
(3) "In 60% of the households in which the man doesn't work, the woman also doesn't work". So:
3y/5=18...> y=30. T/4, the number of households in which men work is 60.
(m+mw)+(w+mw)=70+40=110
m+w+mw=82
mw=110-82=28
ANS: C
(1) The number of households where neither the man nor the woman work is 100 - 82 = 18.
(2) "In 30% of the households with the woman not working the man also doesn't work". So:
3x/10=18...> x=60. T/4, the number of households in which women work is 40.
(3) "In 60% of the households in which the man doesn't work, the woman also doesn't work". So:
3y/5=18...> y=30. T/4, the number of households in which men work is 60.
(m+mw)+(w+mw)=70+40=110
m+w+mw=82
mw=110-82=28
ANS: C
19 Jan 2022, 23:30
Kudos
Bookmarks
Let the total number of households be 100, the number of households in which women don't work be 'x' and the number of households in which the men don't work be 'y'. Also, let the number of households where only women work be 'w', where only men work be 'm' and where both women and men work be 'mw'.
(1) The number of households where neither the man nor the woman work is 100 - 82 = 18.
(2) "In 30% of the households with the woman not working the man also doesn't work". So:
3x/10=18...> x=60. T/4, the number of households in which women work is 40.
(3) "In 60% of the households in which the man doesn't work, the woman also doesn't work". So:
3y/5=18...> y=30. T/4, the number of households in which men work is 60.
(m+mw)+(w+mw)=70+40=110
m+w+mw=82
mw=110-82=28
ANS: C
(1) The number of households where neither the man nor the woman work is 100 - 82 = 18.
(2) "In 30% of the households with the woman not working the man also doesn't work". So:
3x/10=18...> x=60. T/4, the number of households in which women work is 40.
(3) "In 60% of the households in which the man doesn't work, the woman also doesn't work". So:
3y/5=18...> y=30. T/4, the number of households in which men work is 60.
(m+mw)+(w+mw)=70+40=110
m+w+mw=82
mw=110-82=28
ANS: C
