GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Jun 2018, 18:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A rectangular wall is covered entirely with two kinds of dec

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 46167
A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

04 Feb 2014, 06:30
5
23
00:00

Difficulty:

85% (hard)

Question Stats:

55% (01:52) correct 45% (01:25) wrong based on 595 sessions

### HideShow timer Statistics

A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 46167
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

04 Feb 2014, 06:46
10
2
Bunuel wrote:
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

The number of jumbo tiles = x.
The number of regular tiles = 2x.

Assume the ratio of the dimensions of a regular tile is a:a --> area = a^2.
The dimensions of a jumbo tile is 3a:3a --> area = 9a^2.

The area of regular tiles = 2x*a^2 = 80.
The area of jumbo tiles = x*9a^2 = 4.5(2x*a^2 ) = 4.5*80 = 360.

Total area = 80 + 360 = 440.

_________________
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1837
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

04 Mar 2014, 03:15
8
3
Let small tile dimension = 1 x 1 = 1 Square feet.......... (1)

So big tile dimension would be = 3 x 3 = 9 Square feet

80 small tiles are required to cover 80sq feet area

2/3rd of the tiles are small, so 2/3 are 80, then remaining 1/3 would be 40

So 40 big tiles are used = 40 * 9 = 360 Sq feets

Total Area = 360+80 = 440 = Answer = D
_________________

Kindly press "+1 Kudos" to appreciate

Manager
Joined: 05 Jun 2012
Posts: 89
Schools: IIMA
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

11 Apr 2014, 01:00
4
1
easiest way :

2/3 is equal to 80 , so 1/3 will be equal to 40 . As given lenght and width is 3 times so 3*3(area of rectangle l*h) ; are would be 9 times 40*9=360

total area would be =360+80=440
_________________

If you are not over prepared then you are under prepared !!!

Intern
Joined: 15 May 2013
Posts: 17
GPA: 3.3
WE: Other (Consulting)
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

16 Apr 2014, 14:25
Bunuel wrote:
Bunuel wrote:
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

The number of jumbo tiles = x.
The number of regular tiles = 2x.

Assume the ratio of the dimensions of a regular tile is a:a --> area = a^2.
The dimensions of a jumbo tile is 3a:3a --> area = 9a^2.

The area of regular tiles = 2x*a^2 = 80.
The area of jumbo tiles = x*9a^2 = 4.5(2x*a^2 ) = 4.5*80 = 360.

Total area = 80 + 360 = 440.

Hi B,

Though it will not change the answer, should not we consider the tiles to be rectangular, instead of square.
as the ratio could have been different, and that would require us to consider Length and Width differently. Suggest if there is something I'm missing out on!

The number of jumbo tiles = x.
The number of regular tiles = 2x.

Assume the ratio of the dimensions of a regular tile is L:B --> area = L*B.
The dimensions of a jumbo tile is 3L:3B --> area = 9(L*B).

The area of regular tiles = 2x*L*B = 80.
The area of jumbo tiles = x*9(L*B) = 4.5(2x*L*B ) = 4.5*80 = 360.

Total area = 80 + 360 = 440.

_________________

GMAT - I'm gonna eat you whole ..!!

Manager
Joined: 02 Jul 2012
Posts: 202
Location: India
Schools: IIMC (A)
GMAT 1: 720 Q50 V38
GPA: 2.6
WE: Information Technology (Consulting)
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

16 Oct 2014, 11:31
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

Let the area covered by regular tiles be x.
The ratio of number of jumbo tile to regular tiles = 1 / 2
The length and width of the jumbo tiles are 3 times that of the regular tiles.
Thus area of jumbo tiles = 9x/2

x = 80
9x/2 = 360

Thus total area = 360 + 80 = 440
_________________

Give KUDOS if the post helps you...

Manager
Status: folding sleeves up
Joined: 26 Apr 2013
Posts: 148
Location: India
Concentration: Finance, Strategy
GMAT 1: 530 Q39 V23
GMAT 2: 560 Q42 V26
GPA: 3.5
WE: Consulting (Computer Hardware)
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

30 Oct 2014, 09:40
Bunuel wrote:
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

I am not sure how you guys are assuming it to be a square tile. Here is my sol

Regular 2x/3
length L
width w

lw*2x/3=80

lwx= 120--------<1>

Jumbo x/3
length : 3l
width :3w (since ratio of l:w of jumbo is same as regular)

area covered will be 3(lwx) = 3(120)= 360

total area =360+80= 440
Current Student
Joined: 06 Mar 2014
Posts: 257
Location: India
GMAT Date: 04-30-2015
A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

10 Nov 2014, 09:03
1
Here's a simple straight forward solution:

Let Number of tiles be $$T.$$

Jumbo tiles:-
no. of tiles: $$j$$
Length: $$Lj$$
Width: $$Wj$$

Regular tiles:-
no.: $$r$$
Length: $$Lr$$
Width: $$Wr$$

Given
a) $$j = T/3, r = 2T/3$$
b) $$Lj = 3Lr$$ also $$Lj/Wj = Lr/Wr$$ , from this follows -> $$Wj = 3 Wr$$

c) Area of Regular tiles = $$80$$
no. of regular tiles * Area of one Regular tile

$$(r) * (Lr * Wr) = 80$$ --------> $$(Lr * Wr) = 80/r$$

Now to get Area of jumbo tiles, we will do little and only work:
no. of Jumbo tiles * Area of one Jumbo tile

$$Area Jumbo =$$ $$(j) * (Lj * Wj)$$

Using our deductions from " b) " and using values of 'j' and 'r' above, and placing it in the equation above -:
$$Area Jumbo =$$ $$T/3* (3Lr * 3Wr)$$

->$$T/3* 9 (80/r)$$

place$$r = 2T/3$$ above we get

360

Total area = 80 + 360 = 440

P.S. Tried to simplify it too much for everyone, otherwise its a 3 step process.
Intern
Joined: 30 Jul 2008
Posts: 19
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

11 Jul 2015, 03:32
Bunuel wrote:
Bunuel wrote:
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

The number of jumbo tiles = x.
The number of regular tiles = 2x.

Assume the ratio of the dimensions of a regular tile is a:a --> area = a^2.
The dimensions of a jumbo tile is 3a:3a --> area = 9a^2.

The area of regular tiles = 2x*a^2 = 80.
The area of jumbo tiles = x*9a^2 = 4.5(2x*a^2 ) = 4.5*80 = 360.

Total area = 80 + 360 = 440.

can anyone pls. tell me how the ratio of jumbo to regular tiles became 1:2?

Is it given? not able to figure out.
Math Expert
Joined: 02 Sep 2009
Posts: 46167
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

11 Jul 2015, 03:35
robinpallickal wrote:
Bunuel wrote:
Bunuel wrote:
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

The number of jumbo tiles = x.
The number of regular tiles = 2x.

Assume the ratio of the dimensions of a regular tile is a:a --> area = a^2.
The dimensions of a jumbo tile is 3a:3a --> area = 9a^2.

The area of regular tiles = 2x*a^2 = 80.
The area of jumbo tiles = x*9a^2 = 4.5(2x*a^2 ) = 4.5*80 = 360.

Total area = 80 + 360 = 440.

can anyone pls. tell me how the ratio of jumbo to regular tiles became 1:2?

Is it given? not able to figure out.

1/3 of the tiles are jumbo tiles and the remaining, so 2/3, are regular tile:

(jumbo)/(regular) = (1/3):(2/3) = 1:2.
_________________
Intern
Joined: 30 Jul 2008
Posts: 19
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

11 Jul 2015, 03:51
Oh...missed that part....got it.

Thanks a lot Bunuel..
VP
Joined: 07 Dec 2014
Posts: 1018
A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

Updated on: 26 Jul 2016, 18:31
ratio of r/j tile #=2:1
ratio of r/j tile size=(3*2):(9*6)=1:9
80+(r/2)(9*80/r)=440 square feet

Originally posted by gracie on 26 Jul 2016, 15:00.
Last edited by gracie on 26 Jul 2016, 18:31, edited 1 time in total.
Current Student
Joined: 18 Oct 2014
Posts: 882
Location: United States
GMAT 1: 660 Q49 V31
GPA: 3.98
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

26 Jul 2016, 18:06
Bunuel wrote:
A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 80 square feet of the wall, and no tiles overlap, what is the area of the entire wall?

A. 160
B. 240
C. 360
D. 440
E. 560

2/3rd of the tiles are regular tiles with an area of 80 sq ft

2/3*l*b= 80
l*b= 80*3/2= 120

Since the ratio of L/B = l/b, and L is 3l. Therefore, B=3b

1/3rd of the area covered by jumbo tiles:-
1/3 L*B= 1/3 *3l *3b= 3lb= 360

Total area= area covered by jumbo tiles+ area covered by regular tiles= 360+80= 440

_________________

I welcome critical analysis of my post!! That will help me reach 700+

EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 11800
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: 340 Q170 V170
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

03 Feb 2018, 16:31
Hi All,

This question is loaded with little details. You'll need to take lots of notes, stay organized and do some basic math to get the correct answer.

We're told that there are two types of tiles: REGULAR and JUMBO.

Now come all of the little math facts you have to take note of (and deduce)…..
1) 1/3 of the tiles are JUMBO tiles.

Since 1/3 are JUMBO, the other 2/3 are REGULAR.
This means that the ratio of JUMBO:REGULAR = 1:2; in other words, there are twice as many REGULAR tiles as JUMBO tiles.

2) JUMBO tiles have a length that is 3 TIMES that of the REGULAR tiles AND has the same ratio of length:width as the REGULAR tiles.

We'll come back to this information in a moment.

3) REGULAR tiles cover 80 square-feet of the wall.

Since we weren't given any information about the dimensions of the REGULAR tiles, we can TEST VALUES. Let's say….

1 REGULAR tile = 1ft x 1ft.

Since REGULAR tiles cover 80 square feet, that means there are 80 REGULAR tiles.

Now, let's go back to the 2nd piece of information…..

JUMBO TILES have 3 times the length and the same ratio of length:width as REGULAR tiles.

1 REGULAR tile = 1ft x 1ft.
1 JUMBO tile = 3ft x 3ft.

NOW, let's go back to the 1st piece of information…..

The ratio of JUMBO:REGULAR = 1:2

80 REGULAR tiles (each 1ft x 1ft)
40 JUMBO tiles (each 3ft x 3ft).

Total area of the wall = 80(1)(1) + 40(3)(3) = 80 + 360 = 440 square feet

GMAT assassins aren't born, they're made,
Rich
_________________

760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

# Rich Cohen

Co-Founder & GMAT Assassin

Special Offer: Save \$75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee
www.empowergmat.com/

***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************

Manager
Status: Enjoying the Journey
Affiliations: ND
Joined: 26 Sep 2017
Posts: 107
Schools: Rotman '21
WE: Marketing (Consulting)
Re: A rectangular wall is covered entirely with two kinds of dec [#permalink]

### Show Tags

06 Feb 2018, 07:54
Number of Tiles R:J = $$2/3$$ : $$1/3$$ ---- J=$$R/2$$ ===> 1

Dimensions of the tiles R=LW & J=3L*3W=9LW ===> 2

Total area of the wall= (LW) * Total number of tiles
From 1&2: Total area of the wall= (LW)*[R+9$$R/2$$] = 80 + 9$$(90/2)$$= 80+360= 440
_________________

"Giving kudos" is a decent way to say "Thanks" and motivate contributors. Please use them, it won't cost you anything

High achievement always takes place in the framework of high expectation Charles Kettering
If we chase perfection we can catch excellence Vince Lombardi

GMAT Club Live: 5 Principles for Fast Math: https://gmatclub.com/forum/gmat-club-live-5-principles-for-fast-math-251028.html#p1940045
The Best SC strategies - Amazing 4 videos by Veritas: https://gmatclub.com/forum/the-best-sc-strategies-amazing-4-videos-by-veritas-250377.html#p1934575

Re: A rectangular wall is covered entirely with two kinds of dec   [#permalink] 06 Feb 2018, 07:54
Display posts from previous: Sort by