GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 24 May 2020, 15:42

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

### Show Tags

17 May 2017, 23:17
19
00:00

Difficulty:

45% (medium)

Question Stats:

72% (03:21) correct 28% (03:11) wrong based on 178 sessions

### HideShow timer Statistics

A retail store employs only clerks and managers and the clerks earn $11.50/hour while the managers earn$19/hour. Last year, the store had 20 employees and its average employee earned $13/hour. Thus far this year, the store has hired 4 clerks and promoted some of last year’s clerks to manager. If the store has undergone no other personnel changes and the average employee now earns$14/hour, how many clerks were promoted to manager?

A. 2
B. 4
C. 6
D. 7
E. 8

_________________
Intern
Joined: 21 Jun 2013
Posts: 35

### Show Tags

18 May 2017, 05:05
Bunuel wrote:
A retail store employs only clerks and managers and the clerks earn $11.50/hour while the managers earn$19/hour. Last year, the store had 20 employees and its average employee earned $13/hour. Thus far this year, the store has hired 4 clerks and promoted some of last year’s clerks to manager. If the store has undergone no other personnel changes and the average employee now earns$14/hour, how many clerks were promoted to manager?

A. 2
B. 4
C. 6
D. 7
E. 8

let x be the number of clerks who got promoted.
(1) $$\frac{(11.5C + 19M)}{(C+M)}$$ = 13
(2) $$\frac{(11.5(C+4-X) + 19(M+x))}{(C+M+4)}$$ = 14
(3) C+M = 20

From (1) & (3); C=16,M=4
substitute C,M into (2);x = 4
Senior Manager
Joined: 24 Apr 2016
Posts: 306
Re: A retail store employs only clerks and managers and the clerks earn $1 [#permalink] ### Show Tags 18 May 2017, 10:12 1 Given: clerks earn$11.50/hour
managers earn $19/hour Total Number of Clerks currently working = c Total Number of Managers currently working = m Given c+m=20 11.50c+19m = (c+m)13 Solving above two: 11.5c+19m = 13c+13m 6m = 1.5c c=4m 4m+m=20 m=4 c=16 This year, 'n' clerks were promoted to manager c= 16+4-n m=4+n (20-n)11.5+(4+n)19 = (20-n+4+n)14 230-11.5n+76+19n=336 7.5n = 336-306 = 30 n=4 Answer is B Senior PS Moderator Joined: 26 Feb 2016 Posts: 3253 Location: India GPA: 3.12 Re: A retail store employs only clerks and managers and the clerks earn$1  [#permalink]

### Show Tags

18 May 2017, 10:46
a+b=20(where a is number of clerks and b the number of manager)
Also 11.5a+19b=13*20=260

Solving for both the equations(19a+19b=380,11.5a+19b=260) and substracting, we will get 7.5a=120 or a=16)

Now since 4 new clerks were added and few members were promotes, we have 20-x clerks now and 4+x managers.

Also given that
11.5(20-x) + 19(4+x) = 24*14
230 + 76 + 7.5x = 336
7.5x = 30 or x=4(Option B)

Sent from my LG-H818 using GMAT Club Forum mobile app
_________________
You've got what it takes, but it will take everything you've got
Current Student
Joined: 10 Nov 2016
Posts: 47
Location: India
GMAT 1: 730 Q50 V39

### Show Tags

04 Jun 2017, 01:44
2
Here's the shortcut to do this question in 30 seconds!
Solution - think of this problem as an expenditure problem! there were 20 employees, $13.00 avg salary - Total expenditure is$260
4 employees are added, total employees now is 24, $14.00 avg. salary - Total expenditure is$336
Extra expenditure is $76 for the 4 clerks that are added, it's$46, remaining amount is $30 ($76-$46) and this$30 is expenditure for promotions. each promotion cost $7.5 ($19-$11.5), so divide 30 by$7.5 - you can 4. 4 clerks were promoted! Hope you will find it easier and faster!
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 10533
Location: United States (CA)

### Show Tags

09 Apr 2020, 15:41
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________