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# A runs in the clockwise direction on a circular track whereas B runs

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Math Expert
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A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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10 Jan 2020, 02:24
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75% (hard)

Question Stats:

55% (02:50) correct 45% (02:43) wrong based on 65 sessions

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A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions

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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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19 Jan 2020, 19:34
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Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions

Since they are moving in opposite directions, their combined speed will be 25 + 40 = 65 m/s
Of every 65 m, A runs 25m and B runs 40m. Say the length of the track is 65m.

The 10th meeting will happen when they cover 10 circles together = 65*10 = 650 m together.

A will cover 25/65 * 650 = 250 m out of this total in clockwise direction which is 3 full circles + 55m.

The 55m will be 55/65 = 11/13th of the circular track.
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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10 Jan 2020, 02:39
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Suppose the length of track= 65m

Distance travelled by A till their 10th meeting= 25*10=250 m

250 leaves 55 remainder when divided by 65.

fraction of the track-length, measured in clockwise direction from the starting point, at which the 10th meeting takes place= 55/65= 11/13

Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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17 Jan 2020, 09:52
Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions

VeritasKarishma Bunuel chetan2u can someone explain this in more detail? Thanks.
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A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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17 Jan 2020, 19:21
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since A and B both travel in opposite directions
time t meet when they both meet in 1st round
= $$\frac{L}{ (25+40)}$$ where L is length of track
hence time to meet for 10th time would be$$\frac{ 10 L}{ (65)}$$
since we are asked in clock wise direction
hence how far will A be when he meet 10th ime
in $$\frac{10 L}{ (65)}$$ time he would have travelled
$$\frac{10 L}{ (65) *25}$$ metres
=$$\frac{50L}{13}$$
or $$\frac{39 +11 }{13} *L$$
or $$3L + \frac{11}{13} L$$
Hence they would have met in 11/13 L direction from clock wise position
D
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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17 Jan 2020, 20:00
1
Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions

Hi exc4libur

One should know that the distance covered will be in opposite ratio of their speed.
So A:B in speed is 25:40=5:8, so distances covered by them will be in ratio 8:5.

Now whenever both meet, they complete one circle, so they will cover 10 circles when they meet 10th time.
So A will cover 10*5/(5+8) =50/13=(39+11)/13=3 + 11/13

So A would have covered 3 complete circles and would be at 11/13 of 4th circle.
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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18 Jan 2020, 04:19
chetan2u wrote:
Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.
B. $$(\frac{9}{13})^{th}$$ of the track length.
C. $$(\frac{10}{13})^{th}$$ of the track length.
D. $$(\frac{11}{13})^{th}$$ of the track length.
E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions

Hi exc4libur

One should know that the distance covered will be in opposite ratio of their speed.
So A:B in speed is 25:40=5:8, so distances covered by them will be in ratio 8:5.

Now whenever both meet, they complete one circle, so they will cover 10 circles when they meet 10th time.
So A will cover 10*5/(5+8) =50/13=(39+11)/13=3 + 11/13

So A would have covered 3 complete circles and would be at 11/13 of 4th circle.

Thanks chetan2u!! I found what I was doing wrong, I was calculating the final distance for anti-clockwise, instead of clockwise.
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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04 Mar 2020, 05:53
Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Two person with speed x and y runs in a round track D.

Since Speed (A): Speed (B) = 40/25 = 8/5. It's easy to use the variable D as 13, so when A&B meet, A has run 8/13 round and B has run 5/13 round to meet each other.

So, after 10 times A&B meet, B has run 5/13*10D = 50/13 = 3 + 11/13D.

IMO D
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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05 Mar 2020, 23:38
Let the circumference of the track be 13 meters (sum of the ratios of the speeds of A and B). If they start from point S, when they meet the 1st time, A will have run 5m and B 8m (since the ratio of their speeds is 5:8). Let the point of the 1st meeting be denoted by S1 and subsequent meetings by S2, S3... etc. By the time they meet the second time at S2, A will have run a further 5m from S1 (i.e. 5*2m from S). So by the time they meet at S10, A will have run 5*10=50m which is 50/13 (3 & 11/13) revolutions of the circular track. So the 10th meeting takes place at a point which is 11/13th of the track length measured clock-wise from the first starting point S. ANS: D
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Re: A runs in the clockwise direction on a circular track whereas B runs  [#permalink]

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31 Mar 2020, 08:20
Bunuel wrote:
A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

A. $$(\frac{8}{13})^{th}$$ of the track length.

B. $$(\frac{9}{13})^{th}$$ of the track length.

C. $$(\frac{10}{13})^{th}$$ of the track length.

D. $$(\frac{11}{13})^{th}$$ of the track length.

E. $$(\frac{12}{13})^{th}$$ of the track length.

Are You Up For the Challenge: 700 Level Questions

Given: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anti-clockwise direction, but they start from the same point.

Asked: If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the track-length, measured in clockwise direction from the starting point, does the 10th meeting take place?

Their relative speed = 25 + 40 = 65 m/s

Since A runs in clock-wise direction, portion of track covered by him when they first met = 25/65 = 5/13

Portion of track covered by him when they met for 10th time = 50/13 = 3 11/13 = 3 full rounds and 11/13th of the track in clock-wise direction

IMO D
Re: A runs in the clockwise direction on a circular track whereas B runs   [#permalink] 31 Mar 2020, 08:20
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