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A runs in the clockwise direction on a circular track whereas B runs
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10 Jan 2020, 02:24
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A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level Questions
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Re: A runs in the clockwise direction on a circular track whereas B runs
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19 Jan 2020, 19:34
Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level QuestionsSince they are moving in opposite directions, their combined speed will be 25 + 40 = 65 m/s Of every 65 m, A runs 25m and B runs 40m. Say the length of the track is 65m. The 10th meeting will happen when they cover 10 circles together = 65*10 = 650 m together. A will cover 25/65 * 650 = 250 m out of this total in clockwise direction which is 3 full circles + 55m. The 55m will be 55/65 = 11/13th of the circular track.
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Re: A runs in the clockwise direction on a circular track whereas B runs
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10 Jan 2020, 02:39
Suppose the length of track= 65m Distance travelled by A till their 10th meeting= 25*10=250 m 250 leaves 55 remainder when divided by 65. fraction of the tracklength, measured in clockwise direction from the starting point, at which the 10th meeting takes place= 55/65= 11/13 Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level Questions



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Re: A runs in the clockwise direction on a circular track whereas B runs
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17 Jan 2020, 09:52
Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level Questions VeritasKarishma Bunuel chetan2u can someone explain this in more detail? Thanks.



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A runs in the clockwise direction on a circular track whereas B runs
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17 Jan 2020, 19:21
since A and B both travel in opposite directions time t meet when they both meet in 1st round = \(\frac{L}{ (25+40)}\) where L is length of track hence time to meet for 10th time would be\(\frac{ 10 L}{ (65)}\) since we are asked in clock wise direction hence how far will A be when he meet 10th ime in \(\frac{10 L}{ (65)}\) time he would have travelled \(\frac{10 L}{ (65) *25}\) metres =\( \frac{50L}{13}\) or \(\frac{39 +11 }{13} *L\) or \(3L + \frac{11}{13} L\) Hence they would have met in 11/13 L direction from clock wise position D
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Re: A runs in the clockwise direction on a circular track whereas B runs
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17 Jan 2020, 20:00
Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level QuestionsHi exc4libur One should know that the distance covered will be in opposite ratio of their speed. So A:B in speed is 25:40=5:8, so distances covered by them will be in ratio 8:5. Now whenever both meet, they complete one circle, so they will cover 10 circles when they meet 10th time. So A will cover 10*5/(5+8) =50/13=(39+11)/13=3 + 11/13 So A would have covered 3 complete circles and would be at 11/13 of 4th circle.
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Re: A runs in the clockwise direction on a circular track whereas B runs
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18 Jan 2020, 04:19
chetan2u wrote: Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level QuestionsHi exc4libur One should know that the distance covered will be in opposite ratio of their speed. So A:B in speed is 25:40=5:8, so distances covered by them will be in ratio 8:5. Now whenever both meet, they complete one circle, so they will cover 10 circles when they meet 10th time. So A will cover 10*5/(5+8) =50/13=(39+11)/13=3 + 11/13 So A would have covered 3 complete circles and would be at 11/13 of 4th circle. Thanks chetan2u!! I found what I was doing wrong, I was calculating the final distance for anticlockwise, instead of clockwise.



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Re: A runs in the clockwise direction on a circular track whereas B runs
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04 Mar 2020, 05:53
Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place?
A. \((\frac{8}{13})^{th}\) of the track length.
B. \((\frac{9}{13})^{th}\) of the track length.
C. \((\frac{10}{13})^{th}\) of the track length.
D. \((\frac{11}{13})^{th}\) of the track length.
E. \((\frac{12}{13})^{th}\) of the track length.
Two person with speed x and y runs in a round track D. Since Speed (A): Speed (B) = 40/25 = 8/5. It's easy to use the variable D as 13, so when A&B meet, A has run 8/13 round and B has run 5/13 round to meet each other. So, after 10 times A&B meet, B has run 5/13*10D = 50/13 = 3 + 11/13D. IMO D



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Re: A runs in the clockwise direction on a circular track whereas B runs
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05 Mar 2020, 23:38
Let the circumference of the track be 13 meters (sum of the ratios of the speeds of A and B). If they start from point S, when they meet the 1st time, A will have run 5m and B 8m (since the ratio of their speeds is 5:8). Let the point of the 1st meeting be denoted by S1 and subsequent meetings by S2, S3... etc. By the time they meet the second time at S2, A will have run a further 5m from S1 (i.e. 5*2m from S). So by the time they meet at S10, A will have run 5*10=50m which is 50/13 (3 & 11/13) revolutions of the circular track. So the 10th meeting takes place at a point which is 11/13th of the track length measured clockwise from the first starting point S. ANS: D



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Re: A runs in the clockwise direction on a circular track whereas B runs
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31 Mar 2020, 08:20
Bunuel wrote: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? A. \((\frac{8}{13})^{th}\) of the track length. B. \((\frac{9}{13})^{th}\) of the track length. C. \((\frac{10}{13})^{th}\) of the track length. D. \((\frac{11}{13})^{th}\) of the track length. E. \((\frac{12}{13})^{th}\) of the track length. Are You Up For the Challenge: 700 Level QuestionsGiven: A runs in the clockwise direction on a circular track whereas B runs on the same track but in the anticlockwise direction, but they start from the same point. Asked: If their speeds are 25 m/s and 40 m/s respectively, at what fraction of the tracklength, measured in clockwise direction from the starting point, does the 10th meeting take place? Their relative speed = 25 + 40 = 65 m/s Since A runs in clockwise direction, portion of track covered by him when they first met = 25/65 = 5/13 Portion of track covered by him when they met for 10th time = 50/13 = 3 11/13 = 3 full rounds and 11/13th of the track in clockwise direction IMO D




Re: A runs in the clockwise direction on a circular track whereas B runs
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31 Mar 2020, 08:20






