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A salesperson who had been driving at a speed of 100 kilometers per ho 20 Apr 2020, 10:39
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A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
(1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02
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B
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A salesperson who had been driving at a speed of 100 kilometers per ho 21 Apr 2020, 09:37
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gmatt1476
A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
(1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02

Now, the speed reduced by 100-47=53kmph...

All you have to do is convert 53 km into miles, so 53*0.625.
Now 53*0.625>50*0.6 or >30...Eliminate A
53*0.625<53*1 or <53....Eliminate C, D and E

Answer B
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A salesperson who had been driving at a speed of 100 kilometers per ho Updated on: 17 May 2021, 07:20
Originally posted by BrentGMATPrepNow on 28 Apr 2020, 09:32.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:20, edited 2 times in total.
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gmatt1476
A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
(1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02

A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour.
Reduction in speed = 100 - 47 = 53 kilometers per hour
We can use equivalent ratios to convert 53 kilometers per hour to miles per hour.

We are told that 1 kilometer ≈ 0.625 miles

So, if we use the ratio kilometers/miles, we can express the relationship as: kilometers/miles = 1/0.625
Let x = the desired speed (in mph)
We can now write: 1/0.625 = 53/x
Cross multiply to get: 1x = (53)(0.625) ≈ 33 mph

Answer: B

Cheers,
Brent
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A salesperson who had been driving at a speed of 100 kilometers per ho 21 Apr 2020, 09:30
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gmatt1476
A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
(1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02

net change in speed ; ( 100-47) ; 53 kmph
1 km = .625 miles
so in 1 hour distance ; 53 kmph or say 55 *.625 ; 33 miles
OPTION B
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A salesperson who had been driving at a speed of 100 kilometers per ho 16 May 2020, 02:41
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Bunuel is there a tag specifically to practice such conversion questions? 2021OG seems to have a quite few of this type.
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A salesperson who had been driving at a speed of 100 kilometers per ho 16 May 2020, 02:45
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Kritisood
Bunuel is there a tag specifically to practice such conversion questions? 2021OG seems to have a quite few of this type.

No tag. Check other Conversion problems to practice in Special Questions Directory.
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A salesperson who had been driving at a speed of 100 kilometers per ho 31 May 2020, 13:46
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Difference between the speeds is 100kmpd - 47kmph = 53kmph ≈ 50kmph

1 kilometer ≈ 0.625 mile ≈ 0.6 mlie

Speed in miles per hour ≈ 50*0.6 ≈ 30

Answer has to be slightly greater than 30

Therefore answer is Option B
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A salesperson who had been driving at a speed of 100 kilometers per ho 22 Dec 2020, 15:51
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gmatt1476
A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
(1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02

Reduced kilometers =100-47=53

Reduced miles \(=53*0.625=50*0.7<35 \ and \ 50*0.60>30=33\)

The answer is B
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A salesperson who had been driving at a speed of 100 kilometers per ho 11 Feb 2021, 02:56
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b]SOLUTION:

This is a conversion problem.

Initial speed = 100 kmph

Final Speed = 47 kmph

Reduction = 100 - 47 =53 kmph and as 1kmph =0.625 miles(given),

53 kmph = 53 x (625/1000) = 53 x 5/8 = 265/8 = 33.125 mph

= 33mph(approx.) OPTION B



Hope this helps :thumbsup:
Devmitra Sen(Math)
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A salesperson who had been driving at a speed of 100 kilometers per ho 12 May 2021, 01:02
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A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
(1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02

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Answer: Option B

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A salesperson who had been driving at a speed of 100 kilometers per ho 12 May 2021, 04:06
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Video solution from Quant Reasoning starts at 3:27
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A salesperson who had been driving at a speed of 100 kilometers per ho 11 Jun 2021, 19:01
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Reduction in speed = 100 - 47 = 53 kmph
One has to convert 53 km into miles. Why?
Because the question asks per hour.

So 53*0.625 will give the ans. C, D and E options are out.
The most important word in the question was "approximate"
So we can approximate 0.625 to 0.6 and check. Whatever ans we get is slightly lesser than the actual value(since are multplier has reduced by 0.025)
So 53*6/10= 318/10=31.8
Thus B is the ans
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A salesperson who had been driving at a speed of 100 kilometers per ho 31 May 2023, 22:20
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he salesperson's initial speed was 100 kilometers per hour. To convert this to miles per hour, we use the conversion factor of 0.625 miles per kilometer:

Initial speed in miles per hour = 100 km/h * 0.625 miles/kilometer = 62.5 miles per hour

The salesperson's reduced speed was 47 kilometers per hour. Converting this to miles per hour:

Reduced speed in miles per hour = 47 km/h * 0.625 miles/kilometer = 29.375 miles per hour

To find the reduction in speed, we subtract the reduced speed from the initial speed:

Reduction in speed = 62.5 miles per hour - 29.375 miles per hour = 33.125 miles per hour

Rounding this to the nearest whole number, we find that the speed was reduced by approximately 33 miles per hour
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A salesperson who had been driving at a speed of 100 kilometers per ho 24 Jun 2024, 22:27
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