It is currently 20 Nov 2017, 09:14

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

A school administrator will assign each student in a group

Author Message
VP
Joined: 26 Apr 2004
Posts: 1205

Kudos [?]: 844 [0], given: 0

Location: Taiwan

Show Tags

22 Dec 2004, 10:39
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?

(1) It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it.

(2) It is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it.

Kudos [?]: 844 [0], given: 0

Director
Joined: 19 Nov 2004
Posts: 554

Kudos [?]: 280 [0], given: 0

Location: SF Bay Area, USA

Show Tags

22 Dec 2004, 15:13
The stem looks like this:
3 < m < 13
n <13
and Is n= mK1?

1) 3n = mK2
=> n = m/3 *K2
If m/3 is an integer, it will satisfy the question stem.
m/3 will be an integer only if m=6,9,,12. For the other, it won't
So not an answer as it varies.

2) 13n= mK3
=> n = m/13 *K2
If m/13 is an integer, it will satisfy the question stem.
Since m<13, m/13 will never be an integer.
So this will never provide an answer

So B it is.

Kudos [?]: 280 [0], given: 0

CIO
Joined: 09 Mar 2003
Posts: 460

Kudos [?]: 73 [0], given: 0

Show Tags

24 Dec 2004, 01:09
I agree with B.

If there are less than 13 classrooms, but 13n could be divided amongst them, then the number of students would have do be divisible by the number of classrooms. If it weren't, then the number 13 would have to be divisible by the number of classroom, which isn't possible since there are less than 13 classrooms. So we know that n must be divisible by m.

Same logic will not work in number 1.

Kudos [?]: 73 [0], given: 0

24 Dec 2004, 01:09
Display posts from previous: Sort by