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A six-sided die with faces numbered one through six is rolled twice.

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A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 06 May 2019, 02:35
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

74% (00:55) correct 26% (01:04) wrong based on 68 sessions

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Re: A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 06 May 2019, 03:02
1
Probability of not getting a 2 on the first roll =5/6
Probability of not getting a 2 on the second roll =5/6

Probability of not getting 2 in either turn = 5/6 * 5/6 = 25/36

IMO, Answer is C
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Re: A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 06 May 2019, 05:48
Bunuel wrote:
A six-sided die with faces numbered one through six is rolled twice. What is the probability that the face with the number 2 on it will not be facing upward on either roll?

A. 1/6
B. 2/3
C. 25/36
D. 17/18
E. 35/36

P ( not getting 2 ) 1st roll; 5/6 and 2nd roll; 5/6
IMO 5/6*5/6 ; 25/36
IMO C
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Re: A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 06 May 2019, 07:16
Probability of not getting 2 means getting any number other than 2....so the probability would be 5 numbers out of 6

5/6 * 5/6 = 25/36
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Re: A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 06 May 2019, 08:51
can we do like this ----> 2 comes on both rolls i.e 1/6 * 1/6= 1/36

then substract this from 1 i.e 35/36.


sach24x7 wrote:
Probability of not getting 2 means getting any number other than 2....so the probability would be 5 numbers out of 6

5/6 * 5/6 = 25/36

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Re: A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 06 May 2019, 10:18
btrg wrote:
can we do like this ----> 2 comes on both rolls i.e 1/6 * 1/6= 1/36

then substract this from 1 i.e 35/36.


sach24x7 wrote:
Probability of not getting 2 means getting any number other than 2....so the probability would be 5 numbers out of 6

5/6 * 5/6 = 25/36



You will have to add two more probabilities for 2 on first roll and 2 on second roll and then minus it from 1

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Re: A six-sided die with faces numbered one through six is rolled twice.  [#permalink]

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New post 05 Aug 2019, 02:00
1
Two ways to approach this:
1) Probability that a 2 it is not face up, 'P'
\(\frac{5}{6}*\frac{5}{6}=\frac{25}{36}\)

Straight forward

2) 1- Probability that a 2 is face up '1-P'
Probability two 2s
\(\frac{1}{6}*\frac{1}{6}=\frac{1}{36}\)

Probability 2 on the first die but not on the second
\(\frac{1}{6}*\frac{5}{6}=\frac{5}{36}\)

Probability 2 on the second die but not on the first
\(\frac{5}{6}*\frac{1}{6}=\frac{5}{36}\)

Sum these probabilities together: \(\frac{1}{36}+\frac{5}{36}+\frac{5}{36}=\frac{11}{36}\)

\(1-\frac{11}{36}=\frac{25}{36}\)
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Re: A six-sided die with faces numbered one through six is rolled twice.   [#permalink] 05 Aug 2019, 02:00
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A six-sided die with faces numbered one through six is rolled twice.

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