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17 Oct 2016, 05:58
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Difficulty:
25%
(medium)
Question Stats:
75% (01:37) correct
25%
(01:53)
wrong
based on 110
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A software company contracted its sister network technologies firm to upgrade its network and storage equipment. The sister firm charged the software company only for equipment and labor. What fraction of the total amount paid for the upgrade was the labor charge?
(1) Labor cost was $10,000 less than the total cost of the upgrade.
(2) Without the labor charge, the total cost of the upgrade would have been only 5/6 as much.
(1) Labor cost was $10,000 less than the total cost of the upgrade.
(2) Without the labor charge, the total cost of the upgrade would have been only 5/6 as much.
1. If upgrade cost is 20000, then the labor cost is 1/3rd, where as if upgrade cost is 30000, labour cost is 1/4th.
We can't arrive at an unique solution. Hence, not sufficient
2. If x is the total cost, the cost of the upgrade without labor is 5x/6 of the total cost.
Hence, we can infer that labour cost is x/6. This is sufficient.
Option B is the answer.
We can't arrive at an unique solution. Hence, not sufficient
2. If x is the total cost, the cost of the upgrade without labor is 5x/6 of the total cost.
Hence, we can infer that labour cost is x/6. This is sufficient.
Option B is the answer.
18 Oct 2016, 17:36
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Let E be the equipment cost and L be the labor cost.
fraction for labor charge = L/ (E+L)
1. Labor cost was $10,000 less than the total cost of the upgrade
\(L = (E+L) -$10,000\)
E = $10,000
Fraction = \(\frac{L}{($10,000+ L)}\)
Insufficient.
2. Without the labor charge, the total cost of the upgrade would have been only 5/6 as much.
\(E = \frac{5}{6} * (E+L)\)
E = 5L
fraction = \(\frac{L}{(L+E)}\)
= \(\frac{L}{(L+5L)}\)
= 1/6
Sufficient
Option B
fraction for labor charge = L/ (E+L)
1. Labor cost was $10,000 less than the total cost of the upgrade
\(L = (E+L) -$10,000\)
E = $10,000
Fraction = \(\frac{L}{($10,000+ L)}\)
Insufficient.
2. Without the labor charge, the total cost of the upgrade would have been only 5/6 as much.
\(E = \frac{5}{6} * (E+L)\)
E = 5L
fraction = \(\frac{L}{(L+E)}\)
= \(\frac{L}{(L+5L)}\)
= 1/6
Sufficient
Option B
