A solution contains 8 parts of water for every 7 parts of

Let the total solution is 150 L with 80 L water & 70 L syrup.

To make 40% syrup solution, the result solution must have 90 L syrup and 60 L syrup.

Therefore we are taking 10 L of syrup from initial solution and replacing with water.

using urinary method:
70 L syrup in 150 L solution
10 L syrup in 21.4 L solution

We started by multiplying 10
Now to get to the result we need to divide by 10 => amount of solution to be replaced with water = (21.4/10) = 2.14.

Correct option : C

C it is
total solution 15, Lemonoid = 7
we want to make it 40% lemonoid >> so 6 parts of lemonoid
so we need to remove 1 part of lemonoid
each part of solution has 7/15 lemonoid
that means for 1 part lemonoid will be in 15/7 = 2.14 prt of solution which will be replaced with water

Does anybody else find the question description ambiguous?

"A solution contains 8 parts for every 7 parts of Lemonade syrup"
Your interpretation is that syrup and water relate as 7 and 8.

However, it can also mean that syrup takes 7 parts out of total of 8 parts of solution.

Does it make sense?

Yep. When I read the question, I thought that either the question is worded improperly or the word 'water' after '8 parts' is missing. But I figured that if it is 8 parts solution then the options don't match the answer so it must be 8 parts water. Don't fret!

Can you explain that why the new ration is w/1 = 8/7 ? I thought it be w/6 =8/7..Thanks

8/7 is not the new ratio. Again: we want to remove 1 liter of syrup, but with every 1 liter of syrup comes 8/7 liters of water (because if s=1 then w from w/s=8/7 becomes 8/7), hence in order to remove 1 liter of syrup we should remove total of 1+8/7 liters of mixture.

Hope it's clear.

From 100 hardest questions
Bumping for review and further discussion.

1. Let the number of parts of the original solution be 30.
2.The original solution contains 14 parts lemonade and 16 parts water
3. The new solution contains 12 parts lemonade and 18 parts water
4. Let x parts of solution be replaced. Water replaced is 16x/30
5. x parts of water is added
6. From (2) and (3) we see the net increase in water is 18-16=2 parts
7. From (4) and (5) we see the net increase in water is x-(16x/30) parts
8. Equating (6) and (7) we have x=4.28
9. If we take the total number of parts as 30, the solution removed is 4.28 parts. Therefore for a total of 15 parts, the solution removed is 2.14 parts

The question tells you that in the final solution, lemonade syrup is 40% of the solution i.e. there is 2 parts lemonade syrup for 3 parts of water
It does not imply that the concentration of lemonade syrup is 40% of its initial concentration. The final concentration is actually 40% i.e. 2/5.

My solution with explanation:

Alternative approach, give kudos if you like

Let's say total of 15 liters, 8 of water and 7 of lemonade
Therefore, if we need lemonade to be 60% we need the ratio to be 3:2

Thus we have

2(8+x-8/15x) = 3(7-7/15x)

Solving for 'x' we get 15/7=2.14 (C)

Just to elaborate a little more on this. 2:3 are of course the ratios, in some problems we are asked so that there's an equal amount of both, then we don't need to care about the 2 and 3.

Next, we are basically replacing quantities so if we put x we take away x of the solution. But the 'x' liters of the solution contain part of both lemonade and water, therefore, that's why we use the respective ratios.

Hope its clear now

Cheers
J

Def took longer to rationalize than I would have allowed on test day...anyway, here's my take:

Replacing one part of the solution with water will take away 8/15 of water and 7/15 of Lemonade (and replace it with 15/15 water)...essentially just switching out 7/15 of Lemonade with 7/15 Water for every part removed...

So, from a Lemonade composition perspective:

[7 - (7x/15)]/15 = 4/10

x=15/7

It seems I took a completely different tangent here, can someone please help me:
Let there be total 15l of solution implying 8l water and 7l lemonade. Acc. to the problem, let's take off 'w'l from solution and add 'w'l of water implying:
(8+w)/(15-w)=0.6 solving which gives w=0.525
What's wrong here?

Hi VSabc,

This question is a little tougher than a typical "mixture" question. The prompt tells us to REPLACE some of the existing mixture with pure water (with the goal of turning the new mixture into a 40% syrup mix.

To start, we have 15 total liters -->a mixture that is 8 liters water and 7 liters syrup.

If we pour 1 liter of this mixture into a glass, we would have a liquid that is 7/15 syrup (so a little less than half syrup).

For the mixture to be 15 total liters and 40% syrup, we need the mixture to be 9 liters water and 6 liters syrup.

In basic math terms, we need to pour out enough of the mixture that we remove 1 full liter of syrup; when we pour an equivalent amount of water back in, we'll have 15 total liters (and 6 of them will be syrup). Since each liter is 7/15 syrup......

We need to remove 15/7 liters and replace them with 15/7 liters of pure water.

15/7 is a little more than 2 liters (about 2.14 liters)

Final Answer:
GMAT assassins aren't born, they're made,
Rich

Here is the problem with your equation.

When you took out 'w' lt of solution, the water left is less than 8 lt. So how can total water after replacement be (8 + w) lts? It will 'something less than 8 + w' lts.
Also, the new solution after you replace with water is again 15 lts. So why would you have (15 - w) in the denominator?

Your equation should be

\(\frac{8 - (8/15)*w + w}{15} = 0.6\) (the fraction of water removed will be (8/15) of w)

\(8 + (7/15)*w = 9\)

\(w = 15/7\)

Hi Karishma,

Thanks for explaining it so well. I got it wrong as I thought we have to give answer in terms of lemonade.
So, here can we say that replacing 1 unit of lemonade and 1.14 units of water will serve the purpose ?

Regards,

Gaurav

Yes, you are removing a total of 2.14 units, of which (7/15)*2.14 = 1 unit is lemonade and rest 1.14 units is water.

Note that saying "replace 1 unit of lemonade and 1.14 units of water" is not very logical since you cannot remove the two separately. They are mixed together so you need to remove the solution only. You cannot remove 1 unit of lemonade alone since water will come along with it. So it will be logical to say that we must remove 2.14 units of solution of which 1 unit will be lemonade and rest will be water since solutions are assumed homogeneous.