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22 Nov 2018, 00:40
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D
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Difficulty:
25%
(medium)
Question Stats:
66% (01:12) correct
34%
(01:29)
wrong
based on 65
sessions
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A square is inscribed in a circle with a circumference of 16π√2. What is the area of the square?
A. 32
B. 64
C. 128
D. 256
E. 512
A. 32
B. 64
C. 128
D. 256
E. 512
22 Nov 2018, 01:20
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If a square is inscribed in a circle, diagonal of square will be diameter of circle.
Circumference of circle =2 π r
16π√2 = 2 π r
Diameter = 16 √2 = diagonal of square = a√2
Side of square = 16
Area of square = 256.
Answer D
Circumference of circle =2 π r
16π√2 = 2 π r
Diameter = 16 √2 = diagonal of square = a√2
Side of square = 16
Area of square = 256.
Answer D
eswarchethu135
22 Nov 2018, 01:25
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Diameter of the circle is equal to the diagnol of the square.
\(2\pi r = 16 \pi \sqrt{2}\)
\(2r = 16\sqrt{2}\)
2r = diagnol of square
When diagnol of a square is \(16\sqrt{2}\) then side of the square is 16.
Area of square = \(S^2\) => \(16^2\) => 256.
OPTION: D
\(2\pi r = 16 \pi \sqrt{2}\)
\(2r = 16\sqrt{2}\)
2r = diagnol of square
When diagnol of a square is \(16\sqrt{2}\) then side of the square is 16.
Area of square = \(S^2\) => \(16^2\) => 256.
OPTION: D
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