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A starting line up of a team consists of x men and y women. There are

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A starting line up of a team consists of x men and y women. There are  [#permalink]

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New post 26 Nov 2017, 08:44
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Question Stats:

55% (01:45) correct 45% (02:00) wrong based on 52 sessions

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A starting line up of a team consists of x men and y women. There are also 4 reserve players, 2 of whom are men. If one of the starting players is unable to play and needs to be replaced by one of the reserves, what is the probability that the number of women on the starting team will increase?

(1) x + y = 12
(2) x/y = 1/3

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Re: A starting line up of a team consists of x men and y women. There are  [#permalink]

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New post 27 Nov 2017, 05:59
Bunuel wrote:
A starting line up of a team consists of x men and y women. There are also 4 reserve players, 2 of whom are men. If one of the starting players is unable to play and needs to be replaced by one of the reserves, what is the probability that the number of women on the starting team will increase?

(1) x + y = 12
(2) x/y = 1/3


The number of women in starting team will increase only when a male player in unable to play and is replaced by female player.

Probability of a male player unable to play:: x/(x+y).
Probability of choosing a female replacement = 2C1/4C1=1/2

Combined probability : X/(X+Y)*1/2......(a)

From 1,
x + y = 12, we can't find an answer.

From 2, X/Y=1/3, Dividing the numerator and denominator of (a) by X, 1/2(1+Y/X), or, 1/2(1+3)= 1/8. Hence B.
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Re: A starting line up of a team consists of x men and y women. There are &nbs [#permalink] 27 Nov 2017, 05:59
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A starting line up of a team consists of x men and y women. There are

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