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24 Dec 2014, 08:52
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Tough and Tricky questions: Word Problems.

A taxi company charges $1.75 for the first quarter of a mile and fifteen cents for each additional quarter of a mile. What is the maximum distance someone could travel with$4.90?

A. 4 miles
B. 4 1/4 miles
C. 4 3/4 miles
D. 5 1/2 miles
E. 6 1/4 miles

Kudos for a correct solution.
[Reveal] Spoiler: OA

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Re: A taxi company charges $1.75 for the first quarter of a mile and fifte [#permalink] ### Show Tags 24 Dec 2014, 11:30 1 This post received KUDOS$1.75 for the first quarter of a mile and fifteen cents for each additional quarter of a mile. What is the maximum distance someone could travel with
Distance = 1/4 + [ (4.90 - 1.75) / 0.15 ] * 1/4 = 5 1/2
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Re: A taxi company charges $1.75 for the first quarter of a mile and fifte [#permalink] ### Show Tags 24 Dec 2014, 12:14 Bunuel wrote: Tough and Tricky questions: Word Problems. A taxi company charges$1.75 for the first quarter of a mile and fifteen cents for each additional quarter of a mile. What is the maximum distance someone could travel with $4.90? A. 4 miles B. 4 1/4 miles C. 4 3/4 miles D. 5 1/2 miles E. 6 1/4 miles Kudos for a correct solution. First 1/4 mile = 1.75 Total cost =$4.9

Remaining cost after first 1/4 mile = $4.15 => 4.15/.15 = 5 1/4 miles total 5 1/2 miles Ans D _________________ ------------------------------------- Manager Joined: 10 May 2014 Posts: 142 Re: A taxi company charges$1.75 for the first quarter of a mile and fifte [#permalink]

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24 Dec 2014, 13:22
Convert dollars to cents to make your life easier.

490 = 175 + (15q)
315 = 15q
q = 21

Therefore you´ll have 21 quarters of a mile plus the additional quarter of a mile.
That´s 22/4 miles or 5.5 miles.

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Re: A taxi company charges $1.75 for the first quarter of a mile and fifte [#permalink] ### Show Tags 24 Dec 2014, 22:45 Easy of calculations consider multiplying all numbers by 100 and then doing calculations orally. Subtract 490-175==> 490-200+25==>290+25==> 315 Now divide 315/15= 21. This is the total quarter miles that you will travel with 0.15$. Hence total number of miles =21/4=5miles + 1 quarter.

Add 1st quarter for the intial 1.75$which brings the total to 5 and 1/2 miles. SVP Status: The Best Or Nothing Joined: 27 Dec 2012 Posts: 1838 Location: India Concentration: General Management, Technology WE: Information Technology (Computer Software) Re: A taxi company charges$1.75 for the first quarter of a mile and fifte [#permalink]

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31 Dec 2014, 00:41
Answer = D. 5 1/2 miles

First quarter charge = 1.75

As soon as first quarter travel ends, balance = 4.90 - 1.75 = 3.15

Quarters in balance amount $$= \frac{3.15}{0.15} = 21$$

Total quarters = 1+21 = 22

Total miles $$= \frac{22}{4} = 5 \frac{2}{4} = 5 \frac{1}{2}$$
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Re: A taxi company charges $1.75 for the first quarter of a mile and fifte [#permalink] ### Show Tags 08 Jan 2015, 08:52 Bunuel wrote: Tough and Tricky questions: Word Problems. A taxi company charges$1.75 for the first quarter of a mile and fifteen cents for each additional quarter of a mile. What is the maximum distance someone could travel with $4.90? A. 4 miles B. 4 1/4 miles C. 4 3/4 miles D. 5 1/2 miles E. 6 1/4 miles Kudos for a correct solution. OFFICIAL SOLUTION: (D) If we start out with$4.90 and have to spend $1.75 for the first quarter-mile, we will have$3.15 left to spend on quarter-mile intervals.

Since $3.15/$0.15 = 21, we can buy 21 more quarter-miles, and will travel 22 quarter miles in all:
22 × 1/4 = 5 1/2 miles.

The correct answer is choice (D).
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Re: A taxi company charges $1.75 for the first quarter of a mile and fifte [#permalink] ### Show Tags 19 Dec 2017, 07:54 Bunuel wrote: Tough and Tricky questions: Word Problems. A taxi company charges$1.75 for the first quarter of a mile and fifteen cents for each additional quarter of a mile. What is the maximum distance someone could travel with $4.90? A. 4 miles B. 4 1/4 miles C. 4 3/4 miles D. 5 1/2 miles E. 6 1/4 miles We can let x = the number of ¼-miles traveled with$4.90 and create the following equation:

1.75 + 0.15(x - 1) = 4.90

175 + 15x - 15 = 490

160 + 15x = 490

15x = 330

x = 22

We see that 22 quarter-miles can be traveled with $4.90 and 22 x ¼ = 5 ½ miles. Answer: D _________________ Jeffery Miller Head of GMAT Instruction GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions EMPOWERgmat Instructor Status: GMAT Assassin/Co-Founder Affiliations: EMPOWERgmat Joined: 19 Dec 2014 Posts: 11240 Location: United States (CA) GMAT 1: 800 Q51 V49 GRE 1: 340 Q170 V170 Re: A taxi company charges$1.75 for the first quarter of a mile and fifte [#permalink]

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10 Jan 2018, 20:34
Hi All,

Since the answers are NOT nice 'round' numbers, you can use a variation on TESTing THE ANSWERS - but instead of using the answers that are given, you can use round numbers to eliminate options.

We're told that the first 1/4 mile costs $1.75 and each additional 1/4 mile costs$0.15. We're asked for the maximum distance that could be traveled for $4.90 Based on the answer choices, I'll start with what a 5 mile trip cost... The first mile would cost$1.75 + 3($0.15) =$2.20
Each additional mile would cost 4($0.15) =$0.60
So a 5 mile trip would cost $2.20 + 4($0.60) = $2.20 +$2.40 = $4.60 Since we're dealing with$4.90, we will clearly end up going more than 5 miles (so we can eliminate Answers A, B and C)... but we wouldn't travel that much more than 5 miles... From here, it's fairly easy to determine that the additional $0.30 would get us an extra 1/2 mile. Final Answer: [Reveal] Spoiler: D GMAT assassins aren't born, they're made, Rich _________________ 760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com # Rich Cohen Co-Founder & GMAT Assassin Special Offer: Save$75 + GMAT Club Tests Free
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