1. The question essentially asks us to find the cost of the ride A is going to take and the cost of the ride B is going to take.
2. Let's mark these values as \(S_A\) and \(S_B\), respectively, and calculate them.
3. \(S_A\).
- The base fare is $5.
- No discount is applied to the mileage rates since A is not a student.
- The total distance is 8 miles, which is no more than 10, so they'll be charged with a rate of $M. In other words, the cost from that will be $M\( * \)8 = 8M.
- One suitcase is equivalent to a fare of $3\( * \)1 = $3.
Finally, we can add up the costs and arrive at \(S_A = 5 + 8M + 3 = 8M + 8 = 8(M + 1)\).
4. \(S_B\).
- The base fare is $5.
- A discount is applied to the mileage rates since B is a student.
- The total distance is 30 miles, which is more than 10, so they'll be charged with a rate of $M for 10 miles and a rate of $0.5M for 20 miles. In other words, the cost from that will be $M\( * \)10 + $0.5M\( * \)20 = 10M + 10M = 20M and with a 20% discount, 20M\( * \)(100% - 20%) = 16M.
- Two suitcases are equivalent to a fare of $3\( * \)2 = $6.
Finally, we can add up the costs and arrive at \(S_B = 5 + 16M + 6 = 16M + 11\).
5. The positive difference between \(S_A\) and \(S_B\) is \(S_B - S_A = (16M + 11) - (8M + 8) = 8M + 3\).
6. Our answer will be: Difference - 3 + 8M and Amount paid by A - 8(1 + M).