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A town's oldest inhabitant is x years older than the sum of the ages

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A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 17 Jul 2011, 06:12
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A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets be in 20 years?

A. (J - 50)/3
B. 3(J + 20)/x
C. (J + x - 50)/3
D. (J - x + 60)/3
E. (J + x - 20)/3


The answers is
[Reveal] Spoiler:
(J-X+60)/3 .... But i was trying to solve it using algebra and got a wrong solution. I get this answer if i plug in numbers but i am trying to find the algebraic solution.

(J-X-40)/3 is my answers.

J = X + L + L + L is the initial situation
After 20 years
J + 20 = X + L + L + L + 60 ...(20 years for each triplet so 60 years totally).
(J - X - 40 ) / 3 = L is my answer.

What wrong am i doing ? Since the age asked is after 20 years i also consider adding 20 years to J .

Regards,
Mustu
[Reveal] Spoiler: OA

Last edited by Bunuel on 20 Nov 2014, 07:15, edited 1 time in total.
Renamed the topic, edited the question and added the OA.

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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 17 Jul 2011, 06:22
here it goes:

Oldest inhabitant = sum of age of triplets + X
J = 3L + X so L = (J - X)/3

After 20 years = L + 20

= (J - X)/3 + 20

= (J - X + 60)/3

hope this helps

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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 17 Jul 2011, 13:25
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hi mustu,

the initial eq is J=X+3L, your later equation i.e after 20 yrs J+20 = X+3L +60 is wrong as this is not what is stated. the relationship between J and L is only valid now and not after 20 yrs. therefore, you need to extract L from the initial eq and add 20 to it.

or you can do it as : J=X+Sum of triplets => sum of triplets = (J-X) and after 20 years: sum of triplets = J-X+60 => age of one triplet =(J-X+60)/3
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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 17 Jul 2011, 14:14
Current In 20 yrs

Oldest Inhabitant J = 3L +X 3L+X+20


Lee Triplet 1 L L+20

Lee Triplet 2 L L+20

Lee Triplet 3 L L+20


we are asked to find out triplets age in 20 yrs from now = L+20


from current we have J = 3L+X = > L = (J-X)/3

=> L+20 = (J-X)/3 +20 = (J-X+60)/3

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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 20 Nov 2014, 05:27
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 20 Nov 2014, 07:18
mustu wrote:
A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets be in 20 years?

A. (J - 50)/3
B. 3(J + 20)/x
C. (J + x - 50)/3
D. (J - x + 60)/3
E. (J + x - 20)/3


The answers is
[Reveal] Spoiler:
(J-X+60)/3 .... But i was trying to solve it using algebra and got a wrong solution. I get this answer if i plug in numbers but i am trying to find the algebraic solution.

(J-X-40)/3 is my answers.

J = X + L + L + L is the initial situation
After 20 years
J + 20 = X + L + L + L + 60 ...(20 years for each triplet so 60 years totally).
(J - X - 40 ) / 3 = L is my answer.

What wrong am i doing ? Since the age asked is after 20 years i also consider adding 20 years to J .

Regards,
Mustu


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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 18 Jun 2016, 10:32
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t=age of one triplet
3t=J-x
t=(J-x)/3
t+20=(J-x)/3+20
t+20=(J-x+60)/3

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Re: A town's oldest inhabitant is x years older than the sum of the ages [#permalink]

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New post 20 Oct 2017, 14:08
[quote="mustu"]A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets be in 20 years?

A. (J - 50)/3
B. 3(J + 20)/x
C. (J + x - 50)/3
D. (J - x + 60)/3
E. (J + x - 20)/3


think simply

J - 3L = x

or L = (J - x)/3

in 20 years age of each "L" will be
(J - x)/3 + 20

which implies
(J - x + 60)/3

thanks
8-)

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Re: A town's oldest inhabitant is x years older than the sum of the ages   [#permalink] 20 Oct 2017, 14:08
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A town's oldest inhabitant is x years older than the sum of the ages

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